The failed bulb breaks the circuit so no current can flow - so the other bulb goes out (but is OK).
The other bulb will no longer be lit because the circuit will be incomplete.
It depends on the configuration of the circuit.
Series - current goes to 0
Parallel - current stays the same.
They all go out
series
Lights at home are connected in parallel. (Switches are connected in series with the lights in order to turn them on and off.) This way, each light receives the same voltage. Placing the lights in series would divide the voltage between the lights, reducing the power of each, and it would have the effect that one light burning out would cause all the others on the same circuit to stop working.
its a series connection
The answer to this depends on where the ammeter is in the circuit. Assuming the ammeter is in series with the bulb and no other objects are attached, then the current is 0.4 Amps. Otherwise, your question is unanswerable without more information.
Actually, I have seen this in a respected electronics magazine (Elektor) quite some time ago: A diode (selected to be capable to handle the amps, the voltage and the heat from the bulb - if placed inside the lighting fixture) is used to "cut off" one half of the AC sine wave and thus sending pulses of 120V to an incandescent light bulb, simulating a simple dimming device. The proposal was meant to run 240V bulbs at 50% of their brightness but I am pretty certain this concept can be used to run 120V bulbs from 240V power. One other way of connecting 120V bulbs to 240V would be to connect two 120V bulbs OF THE SAME WATTAGE in SERIES, so the two bulbs form their own voltage divider. Not sure what happens if one bulb burns out - I would expect the other one to blow too, as a dying light bulb represents zero Ohms (plasma/arcing) for a few milliseconds before it goes dark forever.
In a series circuit, all bulbs are necessary to complete the circuit. If one bulb goes out, the circuit is broken, so none of the bulbs would light up.
It goes back to that source
If one of the light bulb goes out, then the rest go out too.
It goes dark It is time for bed well that a stupid answer! here's an answer a surge of electricity goes on the wire and then boom light!
It goes dark It is time for bed well that a stupid answer! here's an answer a surge of electricity goes on the wire and then boom light!
The other components are still connected to the circuit
Electrical goes in. Electromagnetic (heat and light) come out.
A fixture is what the light bulb goes into.
The other light bulb still continues to shine if one light bulb is taken out of a parallel circuit. In a series circuit if one light bulb is removed the other light bulb goes black. This happens because the circuit is incomplete.
bulb goes crazy
Well if you brought a light bulb friom a shop then no but when you put the light bulb in the the thing on where it goes then yes it does because the light is on the you are going down on your power
If one light goes out on a series-parallel connected string, all of the lights in that particular series string will go out. The other parallel strings will not be affected. If you are asking about Christmas tree lights, please note that most modern low voltage bulb designs make the bulb short out, rather than open, when the filament burns out. This keeps the other bulbs in that series string on, although they now have more power and are more likely to also burn out.