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If two numbers have a sum of 64 and the quotient is 7 what are the two numbers?
Updated: 9/17/2023
Wiki User
∙ 12y agoBest Answer
x +y = 64
x divided by Y = 7 So what times seven equals a number close to 64
7x2 = 14
7x3 = 21
7x4 = 28
7 x5 = 35
7x6 = 42
7x7= 49
7x8 = 56 64 - 56 = 8
therefore x = 56 and y = 8 and to prove correct
56 + 8 = 64
56 divided by 8 = 7
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∙ 12y agoThis answer is:
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