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# If you flip a coin 5 times what is the probability that the coin will land on heads all five times?

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The probability that the coin lands on the heads ones: 1/2

Two times (1/2)^2 = 1/4

Five times (1/2)^5 = 1/32 (so 1 in 32 attempts)

n times (1/2)^n

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## Related Questions

There is a 50% chance that it will land on heads each toss. You need to clarify the question: do you mean what is the probability that it will land on heads at least once, exactly once, all five times?

Since a coin has two sides and it was tossed 5 times, there are 32 possible combinations of results. The probability of getting heads three times in 5 tries is 10/32. This is 5/16.

Each coin toss is a Bernoulli trial with a probability of success of .5. The probability of tossing heads exactly 3 times out of five is3 ~ Bin(5, 1/2), which equals(5!/(3!(5-3)!))(0.5^3)(1-0.5)^(5-3), which is 0.3125.

The probability of getting five heads out of 10 tosses is the same as the probablity of getting five tales out of ten tosses. One. It will happen. When this happens, you will get zero information. In other words, this is the expected result.

The probability that you will toss five heads in six coin tosses given that at least one is a head is the same as the probability of tossing four heads in five coin tosses1. There are 32 permutations of five coins. Five of them have four heads2. This is a probability of 5 in 32, or 0.15625. ----------------------------------------------------------------------------------- 1Simplify the problem. It asked about five heads but said that at least one was a head. That is redundant, and can be ignored. 2This problem was solved by simple inspection. If there are four heads in five coins, this means that there is one tail in five coins. That fact simplifies the calculation to five permutations exactly.

The probability of a spinning coin landing on heads is 50% each time. The probability of five consecutive heads is (0.5 x 0.5 x 0.5 x 0.5 x 0.5) = 1/32 = 0.03125 = (3 and 1/8)%

The probability of getting a heads on the first flip is 1/2. Similarly, the probability on each subsequent flip is 1/2, since they are independent events. The probability of several independent events happening together is the product of their individual probabilities.

Five coin flips. Any outcome on a six-sided die has a probability of 1 in 6. If I assume that the order of the outcome does not matter, the same probability can be achieved with five flips of the coin. The possible outcomes of five flips of a coin are as follows: 5 Heads 5 Tails 4 Heads and 1 Tails 4 Tails and 1 Heads 3 Heads and 2 Tails 3 Tails and 2 Heads For six possible outcomes.

If you toss a coin often enough, it is a certainty, so that the probability = 1. The probability of that outcome in the first five tosses of a coin is (1/2)5 = 1/32.

The probability of getting all heads or all tails in 5 flips of a coin is 1 in 16.The probability of getting a head or a tail on the first flip is 1 in 1. The probability of each of the following coins matching the first coin is 1 in 2. Simply multiply the five probabilities (1 in 1) (1 in 2) (1 in 2) (1 in 2) (1 in 2) and you get 1 in 16.It is true that the probability of getting all heads is 1 in 32, and the probability of getting all tails is also 1 in 32. Since the question asked the probability of both cases (all heads or all tails), the answer is 1 in 16.

The probability of any 1 result of tossing a coin 5 times, for example HHTHH or TTTTH, is 1/2^5 = 1/32. To find out how many of these results involve getting 3 heads, say HHHTT or HHTHT, we use the calculation 5!/(3!*2!), which = 10. Finally we multiply these 2 results to get 10/32 = 5/16.

We can simplify the question by putting it this way: what is the probability that exactly one out of two coin flips is a head? Our options are HH, HT, TH, TT. Two of these four have exactly one head. So 2/4=.5 is the answer.

The probability of getting five tails in a row is 1/2^5, or 1 in 32.The probability of getting five heads in a row is 1/2^5, or 1 in 32.Thus, the probability of getting either five heads or five tails in five tosses is 1 in 16.(The caret symbol means "to the power of," as in 2^5 means "2 to the 5th power.")

The total number of outcomes you could get by flipping a coin 4 times is 2^4 or 16 ways as each coin toss yields two possible outcomes (Heads or Tails) and there are four trials. With that said, you need to find out how many ways there are to get 3 heads or 4 heads. You could use combinations to find this: n C r = n! / [ r! (n-r)! ] 4 C 3 = 4! / [ 3! (4-3)! ] 4 C 3 = 4! / 3! 4 C 3 = 4 4 C 4 = 4! / [ 4! (4-4)! ] 4 C 4 = 4! / 4! 4 C 4 = 1 The total numbers of ways that one could get at least 3 H heads is equal to five (4 ways to get three heads, and one way to get 4 heads). So the probability of getting at least 3 heads in four tosses is equal to 5/16 or 31.25%.

1/2. It doesn't matter if it's heads or tails, it's still 1/2. ====== If you are talking about the total result of flipping a coin 5 times, you have 31 chances out of 32 (more than 96 percent) that you will get something other than five tails.

The probability of getting a head on each occasion if a coin is tossed five times is equal to 1/2 x 1/2 x 1/2 x 1/2 x 1/2 (that is, 1/25) = 1/32 or one in thirty-two. The probability of getting a head on the fifth toss is 1/2. All other tosses are independent of the fifth toss. The probability of getting at least one head when tossing the coin 5 times: Since there are 32 possible combinations and only one of those combinations is all tails you could expect to toss a combination with a head 31/32 times. The probability is 0.96875.

The probability of rolling a six with a standard die five times in a row is (1 in 6)5 which equals 1 in 7776 or about 0.0001286.

We need to calculate two things:How many possible possible series of 10 coin flips are there? As we flip 10 times and each time we can have either heads or tails we have 2 by the power of ten possibilities, or a total of 1024 unique possible series.Now, how many of those series have exactly five heads and five tails? Lets assume we have ten "pre filipped" coins at hand - 5 tails and 5 heads. How many possible combinations are there. Well, if they were all different, you would have 10! (10 factorial = 10*9*8*7*6*5*4*3*2*1) possibilities.How ever, the 5 heads are identical and so are the 5 tails, so if I interchange the locations of two coins that are both heads for example I still get the exact same series. There are 5! possible heads combinations, and 5! tails combinations.Thus, the total number of unique combinations is 10!/(5!*5!) which happens to be 252.So, out of 1024 possible series, 252 contain exactly 5 heads.The probability thus is 252/1024=0.24609375 (roughly 25%)

The answer depends on what you are looking for: the full sequence of results, the number of heads (or tails) the number of runs, the lengths of runs, or whatever.

http://wiki.answers.com/Q/If_you_Flip_four_coins_at_once_what_is_probability_of_2_head_and_3_tail" The probability of flipping four coins and getting 2 heads and 3 tails is ZERO 2 heads and 3 tails requires flipping FIVE coins.

Firstly, the probability when tossing a coin and getting a head or tail is 1/2, then rolling a die, there are 6 sides so the chance of rolling any number is 1/6, there are 2 chances of rolling greater than 4 ie 5 and 6, so the probability of rolling a 5 or 6 in 1/3, as these are independent events you multiply the probability getting a heads of tails, (1/2) by the probability of rolling a five or six, (1/3) which gives you 1/6 or 0.1666 recurring.

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