The expected value is the number of tosses times the probability of tails, so:
E(number of tails) = 52 * 1/2 = 52/2 = 26
The answer depends on how many coins were tossed.
The answer depends on the experiment: how many coins are tossed, how often, how many dice are rolled, how often.
The odds that a tossed coin will land tails side down remain one in two no matter how many times the coin has previously been tossed.
The probability of getting two tails in the first two is 1/4. And it does not matter how many more times the coins are tossed after the first two tosses.
Six- hhh ttt hht tth hth tht
There are 4 events: 3 heads, 2 heads 1 tail, 1 head 2 tails, and 3 tails.
If you know which coin is which, there are 16possible outcomes.If you're only counting the number of Heads and Tails, there are 5 .
Out of the 16 possible outcomes for a coin tossed four times, 4 of them result in 3 Tails & 1 Head. They are: TTTH, TTHT, THTT, and HTTT.
10 coins would be tails up.
If we toss three coins 240 times, how many times can we expect the coins to have three tails showing?
The total number of outcomes is 2^5 = 32.
Since each coin would have the outcome with Heads and Tails: Then among the 32 coins, we can have the possible outcomes from no Heads, 1 Head, 2 Heads, ....... , 31 Heads, 32 Heads. Therefore we would have 33 outcomes.
three heads two head, one tails one heads, two tails three tails
I believe there would be 11 possible outcomes!
There are two answers to this question. If it can only land on heads or tails up, then there is a 50% chance ( or half a chance) it will land heads up, but that's not necessarily true. But, if it can land on heads, tails, or sides, then there is a 16% chance it will land tails up.
there could be five possible outcomes: t= tails h= heads t t t t 4 tails t t t h 3 tails 1 head t t h h 2 tails 2 heads t h h h 1 tail 3 heads h h h h 4 heads
Each coin has two possible outcomes, either Heads or Tails. Then the number of outcomes when all 4 coins are tossed is, 2 x 2 x 2 x 2 = 16.
If you toss a fair coin 250 times , about how many times should it land on tails?
8 outcomes are possible in this situtation. You just have to multiply 4 by 2 to get the answer.
9, you just have to multiply for problems like this
Assuming the coins are fair, two-sided coins, and landing on their sides is not an option, there are four possible outcomes if you consider coin a having a head and coin b having a tail being a different instance from coin a being a tail and coin be having a head. Here they are; Coin A | Coin B Heads | Tails Heads | Heads Tails....| Heads Tails....| Tails
This is the same as example 2 in the link below
There are three possibilities, Heads, Tails and stand on edge
Each coin has 2 outcomes. Either being heads or tails. Take the outcome of each coin to the root of the number of coins. (1/2)^3 = .125 = 12.5% or a 1 in 8 chance. Take .125 and times it by 100 to get the probability out off 100 times. .125 x 100 = .125 which = 12.5%= 1 in 8 chance
It depends on how often it is thrown, but it will usually land on its side about 98% of the time.