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45 g MgCl2 x 1 mole MgCl2/95.2 g /0.5 L = 0.9045 moles/L = 0.90 M (to 2 significant figures)

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Q: If you have 45 grams of MgCl2 and dissolved it in 0.5 L. Find the molarity of MgCl2?
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