Math and Arithmetic

Statistics

You can expect to get a 5 about 15 times out of 90.

With a fair die, you would expect it 60*(1/6) = 10 times.

Type your answer here... 15

He should expect it 100 times.

the answer is the probability 6o =1/6 = 60%

the probability 6o =1/6 = 60%

Never. If you roll it 1 time, there can be no "then".

You would expect it 0.3 of the times.

36 times. But also, you might get the opposite result 36 times.

Possible outcomes of one roll = 6Successful outcomes = 1Probability of success on each roll = 1/6Expectation in 150 rolls = (1/6) x (150) = 25 times

If you roll a die 100 times, you would expect to get a 1 about 17 times, because the probability of getting a 1 is 1 in 6, or 0.1667. However, that is theoretical probability; experimental probability - the actual results of doing this 100 times - might not be 17, but if you did this a large number of times, the experimental results would indeed begin to approach the theoretical results.

The expected value is 20 times.

pr(six) = 1/6 → expected 6s in 90 rolls = 1/6 × 90 = 15

If you were really unlucky, infinitely many times! The probability of that happening is very tiny but it is not zero.

The expected number of times is the probability x number of throws. Since you have a prob of 1/6 for a seven, then (1/6) * 160 = 26.67 times you would have success. We generally would round up the expected number of successes to the whole number 27.

You will roll 600 times, of course!

Since a cube has 6 sides, you have a 4 in 6 chance of getting a number less than 5 each time you roll the dice. You would take how many times you want to roll it (360), divide it by the number of sides (6), and multiply it by 4 since you know you have a 4 in 6 chance. So it should be 240. This is strictly mathematical though and you should not consider it accurate since there are many variables when rolling it.

The probability of rolling a four on a single roll of a fair die is 1/6. So the expected number of 4s in 450 rolls is 450*1/6 = 75.

If the dice or die are 6 sided, then you would most likely roll a 6 13.33333 times, which rounds to 13.

There are six possible outcomes. Assuming the probability of each outcome is the same (dice has no defects), then you are likely to roll the number two, 100/6=50/3=16.67 times.

The theoretical probability of rolling a 5 on a standard six sided die is one in six. It does not matter how many times you roll it, however, if you roll it 300 times, the theoretical probability is that you would roll a 5 fifty times.

If this is a homework assignment, please consider trying to answer it yourself first, otherwise the value of the reinforcement of the lesson offered by the assignment will be lost on you.If a number cube (die) contains the numbers 1, 2, 3, 4, 5, and 6, and the cube is fair, then the probability of rolling a 2 is 1 in 6. If you roll the cube 100 times, you would expect to get 2's 100 / 6, or 17 times. However, 100 trials is not a lot of trials, so the experimental outcome might not match the theoretical probability.

Assuming you use two six-sided dice, you can roll a sum of 8 as many times as you want, provided you have enough time to sit there and roll them.

Odds are you would throw 4 twice but that's in an ideal world. Best guess would be 1, 2 or 3 times

Total possible outcomes of one roll = 6Number of primes on the die = 3 (2, 3, and 5)Probability of a prime on each roll = 3/6 = 50% .So, in 300 rolls of a fair die, you would expect approximately 150 primes.

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