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The amount of energy that is consumed by a 1.20 kilowatt hair used used for twelve minutes is approximately fifty seven kilojoules and the amount of energy consumed by an eleven watt night left on for ten hours is approximately twenty five kilojoules.

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10y ago
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12y ago

1200 watts for 15 minutes = 300 watt-hours

100 watts for 1 hour = 100 watt-hours

Total = 400 watt-hours = 0.4 kilowatt-hour of electrical energy

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10y ago

It's easily worked out if you multiply the power by the time to find the energy used in each case.

A 1200 W hair dryer for 5 minutes takes 1200x5 watt-minutes. which is 6000 watt-minutes or 100 watt-hours.

A 60 W lamp for 10 hours takes 600 watt-hours.

So the lamp takes 6 times more energy, which costs 6 times more.

A 12 watt low-energy light provides as much light at one fifth the cost for the energy.

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12y ago

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Q: Which costs more running a 1200-W hair dryer for 5 minutes or leaving a 60-W lamp on overnight 10 hours?
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I'm sure just like everything else there are different sizes, which will make it vary, but you're about to know something that most don't. Volts x Amperes = Watts, or Watts divided by Volts = Amperes. Example say the appliance says 120V and 8Amp you mutiply 120 by 8 = 960Watts. If it says 1200W and 120V then you do 1200 divided by 120 = 10Amperes.


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Yes, an unbalanced load on a split-phase electrical power service can affect the power measurement. The power measurement is calculated based on the current and voltage in the circuit. An unbalanced load means that the current and/or voltage in the different phases of the split-phase system are unequal. This can result in inaccurate power measurements, as the traditional power calculation assumes balanced conditions.


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The amount of energy used is really unrelated to voltage. The energy usage of a piece of equipment is related to the work done, and/or heat generated by that piece of equipment. Electrical power is equal to the voltage times the current (amperage). At 240 volts, the same amount of energy is produced using 1/2 of the current (amperage) draw than is required at 110 V. For instance, a 1200 watt appliance will require 10 amps of current at 120 V (120V x 10A = 1200W). The same appliance will require 5 amps of current to do the same job at 240 V (240V x 5A = 1200W). The energy usage (1200W x time) is the same in both cases.

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