In the formula for calculating a parabola the letters h and k stand for the location of the vertex of the parabola. The h is the horizontal place of the vertex on a graph and the k is the vertical place on a graph.
It depends on where points h and k are, in which parabola. Since you have chosen not to share that information, there cannot be any sensible answer to this question.
Oh! i learnt about 8 different types of parabola! 1] y2 = 4ax 2] y2 = -4ax 3] x2 = 4ay 4] x2 = -4ay 5] (y-k)2 = 4a(x-h) 6) (y-k)2 = -4a(x-h) 7] (x-h)2 = 4a(y-k) 8] (x-h)2 = -4a(y-k)
The focus of a parabola is a fixed point that lies on the axis of the parabola "p" units from the vertex. It can be found by the parabola equations in standard form: (x-h)^2=4p(y-k) or (y-k)^2=4p(x-h) depending on the shape of the parabola. The vertex is defined by (h,k). Solve for p and count that many units from the vertex in the direction away from the directrix. (your focus should be inside the curve of your parabola)
when the function is in vertex form: y = a(x - h)2 + k, the point (h, k) is the vertex.
This equation yx3 k is that of a parabola. The variable h and k represent the coordinents of the vertex. The geometrical value k serves to move the graph of the parabola up or down along the line.
A parabola is not a shape, it is actually a curved line in a coordinate plane. It is shaped like a U turned in any direction. The two basic equations for it are y=a(x-h)2+k or x=a(y-k)2+h.
A parabola with vertex (h, k) has equation of the form: y = a(x - h)² + k → vertex (k, h) = (-2, -3), and a point on it is (-1, -5) → -5 = a(-1 - -2)² + -3 → -5 = a(1)² - 3 → -5 = a - 3 → a = -2 → The coefficient of the x² term is -2.
Y=a(x-h)+k is the vertex formula. Since the vertex is at (-2,-3) this parabola has the equation: y=a(x+2)^2-3 We can plug in x=-1 but we really need to know a, to solve for y. ( we can solve it, but we will have an a in the solution)
A parabola with vertex (h, k) has equation of the form: y = a(x - h)² + k → vertex (k, h) = (2, -1), and a point on it is (5, 0) → 0 = a(5 - 2)² + -1 → 0 = a(3)² -1 → 1 = 9a → a = 1/9 → The coefficient of the x² term is 1/9
A parabola with vertex (h, k) has equation of the form: y = a(x - h)² + k → vertex (k, h) = (3, 5), and a point on it is (-1, 6) → 6 = a(-1 - 3)² + 5 → 6 = a(-4)² + 5 → 1 = 16a → a = 1/16 → The coefficient of the x² term is 1/16
For a parabola with an axis of symmetry parallel to the x-axis, the equation of a parabola is given by: (y - k)² = 4p(x - h) Where the vertex is at (h, k), and the distance between the focus and the vertex is p (which can be calculated as p = x_focus - x_vertex). For the parabola with vertex (1, -3) and focus (2, -3) this gives: h = 1 k = -3 p = 2 - 1 = 1 → parabola is: (y - -3)² = 4×1(x - 1) → (y + 3)² = 4(x - 1) This can be expanded to: 4x = y² + 6y + 13 or x = (1/4)y² + (3/2)y + (13/4)
Formula of a circle in a Cartesian plane: (x-h)^2+ (y-k)^2 = r^2 where the center is at (h,k) and the radius is r.