5 moles RbNO3 (3 moles O2/2 moles RbNO3)
= 7.5 moles oxygen gas produced
2LiBr(aq) + Cl2(g) = 2LiCl(aq) + Br2(l) will result in .167 moles of lithium chloride.
Moles of one substance compared to moles of the second substance. Ex. moles of reactant A compared to moles pf product F
The coefficient (in this case a 2) indicates the number of moles or molecules of the compound. So, 2NH3 means there are 2 moles or 2 molecules of ammonia (NH3).
You cannot convert cm3 to moles. They do not measure the same quantity. Cubic centimeters measure volume (the amount of space an object takes up) and moles measure the amount of a substance. The mole is one of the seven fundamental SI units, whereas cubic centimeters is a derived unit.
Depends on the concentration of the solution and what is in it.
0,044 moles of NH3 can be produced.
8,038 moles of ammonia were produced.
6 moles
2 KClO3 ----> 2KCl + 3O2 So 2 moles of Potassium Chlorate produces 3 moles of oxygen molecules or 6 moles of oxygen atoms. 3 moles of Potassium chlorate would thus produce 4.5 moles of oxygen molecules or 9 moles of oxygen atoms.
2 moles, if you can find the proper catalyst, or set of reactions to complete the reaction.
The thermal decomposition reaction is:2 KO2------------K2O2 + O20,2 moles of O2 are produced from o,4 moles KO2.
Balanced equation. 4Na + O2 -> 2Na2O 10 moles Na (2 moles Na2O/4 moles Na) = 5.0 moles Na2O produced
This reaction? 6Li + N2 --> 2Li3N 0.450 moles Li (2 moles Li3N/6 moles Li) = 0.150 moles lithium nitride produced ===========================
First you need to find the balanced reaction:2S + 3O2 --> 2SO3So using the balanced reaction we see that for every 3 moles of oxygen consumed, 2 moles of sulfur trioxide are produced:1.2 moles O2 consumed * (2 moles SO3/3 moles O2) = 0.8 mole of SO3 produced
It measures the amount of reactants actually produced in a reaction compared to the amount that would theoretically be produced if 100% of the reactants were converted to products according to the stoichiometry of the reaction. It is found by: actual moles of products ÷ predicted moles of products * 100%
Yes, it is possible.
If the reaction were 2AlCl3 + 3Pb ---> 3PbCl2 + 2Al, then from this balanced equation, 14 moles of AlCl3 would produce 3/2 x 14 moles of PbCl2 = 21 moles of PbCl2.