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I wasn't entirely sure what you meant, but if the problem was to find the integral of [sec(2x)-cos(x)+x^2]dx, then in order to get the answer you must follow a couple of steps:
- First you should separate the problem into three parts as you are allowed to with integration. So it becomes the integral of sec(2x) - the integral of cos(x) + the integral of x^2
- Then solve each part separately
The integral of sec(2x) is -(cos(2x)/2)
The integral of cos(x) is sin(x)
The integral of x^2 is
- Lastly you must combine them together:
-(cos(2x)/2) - sin(x) + (x^3)/3
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What is the integral of 1 over x squared plus 1?
arctan(x)
What is the indefinite integral of 3sinx-5cosx?
8
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I will assume that this is sopposed to be integrated with respect to x. To make this problem easier, imagine that the integrand is x raised to the negative 3. The integral is 1/(-2x-2) plus some constant c.
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Do you mean the Convolution Integral?
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The integral of -x2 is -1/3 x3 .
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What is the number of integral solution to x plus y plus z equals 100?
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The integral of 1 + x2 is x + 1/3 x3 + C.
How would you solve the integral of 1 plus tan2x plus tan squared 2x?
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How do you integrate the integral of quantity of x plus 2 divided by x squared plus x plus 1?
3
What is the integral of 1 over x squared plus 1?
arctan(x)
What would be the integral of x where x has power 2?
If x has the power 2 then you want the integral of x2, I think. When you integrate this you get : x3/3 , plus a constant.
The indefinite integral of x2 divided by 4 plus 16?
x3 /12 + 16x + c
What is the integral of 2x square plus 4x minus 3 divided by x plus 2?
If you mean integral[(2x^2 +4x -3)(x+2)], then multiply them out to get: Integral[2x^3+8x^2+5x-6]. This is then easy to solve and is = 2/4x^4+8/3x^3+5/2x^2-6x +c
What is the integral of x divided by x plus 1?
x/(x+1) = 1 - 1/(x + 1), so the antiderivative (or indefinite integral) is x + ln |x + 1| + C,
How do you prove that integral sinx plus cosxsinx-cosx plus 2 cos2xdx equals 3?
Without specifying the limits of integration, the integral will always include an arbitrary constant, and you'll never get a numerical value for it. So the statement is untrue on its face, hence unprovable. We'll have a look at the trig later.
