Top Answer

There are infinitely many of them.

They include

square root of (4.41)

square root of (4.42)

square root of (4.43)

square root of (4.44)

square root of (4.45)

square root of (5.3)

square root of (5.762)

square root of (6)

square root of (6.1)

square root of (6.2)

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0There are an infinite number of irrational numbers between 2 and 4. See the link below for the definition of irrational numbers. The two most popular irrational numbers between 2 and 4 are pi (3.14159...) and e (2.71828...).

Infinitely many. In fact, there are more irrational numbers between 1 and 2 as there are rational numbers - in total. The cardinality of this set is Aleph-0ne.

There are infinitely many irrational numbers between sqrt(2) and sqrt(3).

Irrational numbers are infinitely dense. this means that there are infinitely many irrational numbers between any two numbers and so the term "next" has no meaning.

No, there are more irrational numbers between 1 and 2 than there are rational numbers.

No, not at all. There are more irrational numbers between 1 and 2 than there are rational numbers in total!

No. sqrt(3) - sqrt(2) is irrational.

4*sqrt(2) Rational multiples of irrational numbers are irrational. sqrt(2) is about 1.414, and 5/4 = 1.25 < 1.414... < 1.75 = 7/4 so 4*sqrt(2) is between 5 and 7, and is irrational.

The difference can be rational or irrational.5 + sqrt(3) and 2 + sqrt(3) are both irrational numbers but their difference is[5 + sqrt(3)] - [2 + sqrt(3)] = 3, which is rational.

Irrational numbers can't be expressed as fractions Irrational numbers are never ending decimal numbers The square root of 2 and the value of pi in a circle are examples of irrational numbers

If it is integers, you have -2, -1, 0, 1, 2 and 3. If rational numbers or irrational numbers or real numbers, there are an infinity of them between -3 and 4.

An integer is a whole number. There are lots of other numbers, such as fractions or rationals, and irrational numbers (such as the square root of 2)

There are infinitely many of them. For example, +sqrt(3.1)

[ square root of (2) ] is irrational

No. 4 root 2 and 2 root 2 are both irrational. Divide the first by the second you get 2. Which is not a member of the set of irrational numbers.

Yes. The sum of two irrational numbers can be rational, or irrational.

Find the difference between the two numbers, then add an irrational number between zero and one, divided by this difference, to the lower number. Such an irrational number might be pi/10, (square root of 2) / 2, etc.

Four examples of irrational numbers are 21/2, 31/2, 51/2 & 71/3

Yes.2 and 0.5 are both rational. But 2^0.5, which is sqrt(2), is irrational.

The product of two irrational numbers may be rational or irrational. For example, sqrt(2) is irrational, and sqrt(2)*sqrt(2) = 2, a rational number. On the other hand, (2^(1/4)) * (2^(1/4)) = 2^(1/2) = sqrt(2), so here two irrational numbers multiply to give an irrational number.

sqrt(2.31 and sqrt(2.4)

Two irrational numbers between 0 and 1 could be 1/sqrt(2), Ï�/6 and many more.

Yes. pi - sqrt(2) is irrational.

Yes. sqrt(2) + sqrt(2) = 2*sqrt(2), an irrational number.

Not necessarily. 3+sqrt(2) and 3-sqrt(2) are both irrational numbers. Their sum is 6 - a rational.

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