No, Na+ is neutral and F- is very weakly basic, not acidic.
NaCl (not NaCI) is the chemical formula of sodium chloride; sodium chloride is a salt (table salt), not a base.
No, NaF is a weak base.
weak base.
It is BASIC because, if combined with water, it produces a strong base: NaOH
NaF is a Lewis base. the F- ion has electron pairs that it can donate for bonding.
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I will dissolve in water to form Na+ and F- NaF <-> Na+ + F- ( NaF is not particularly soluble at room temperature so it might need some heating. After this step the F- anion will react with an H2O molecule to create an HF molecule. F- + H2O <-> FH + OH- Note that F- like other halogens is not likely to attack an hydrogen molecule, however what make F- unique is that the bond it creates is so strong that once it is made, it is very difficult to break. As a result the FH form will exist in solution and accumulate up to a certain amount(the bond can still be broken however, so it is not a strong base), hence why F- is a weak base unlike other halogen ions which are neutral.
NaF stands for sodium fluoride.
It is BASIC because, if combined with water, it produces a strong base: NaOH
NaF is a Lewis base. the F- ion has electron pairs that it can donate for bonding.
HCl + NaF -> HF + NaCl
NaF is a salt.
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I will dissolve in water to form Na+ and F- NaF <-> Na+ + F- ( NaF is not particularly soluble at room temperature so it might need some heating. After this step the F- anion will react with an H2O molecule to create an HF molecule. F- + H2O <-> FH + OH- Note that F- like other halogens is not likely to attack an hydrogen molecule, however what make F- unique is that the bond it creates is so strong that once it is made, it is very difficult to break. As a result the FH form will exist in solution and accumulate up to a certain amount(the bond can still be broken however, so it is not a strong base), hence why F- is a weak base unlike other halogen ions which are neutral.
First recognize that NaF is the salt of a strong base (NaOH) and a weak acid (HF), so the pH will be alkaline. Next, look at the hydrolysis of NaF: NaF + H2O ---> NaOH + HF, or looking at it another way.... F^- + H2O ---> HF + OH- and here F^- acts as a base, so we need the Kb for NaF and that will be the inverse of the Ka for HF. The Ka for HF is 6.6x10^-4, so Kb = 1x10^-14/6.6x10^-4 = 1.5x10^-11. Now, Kb = [HF][OH-]/[F-] = (x)(x)/(0.89) = 1.5x10^-11 x^2 = 1.3x10^-11 x = 3.6x10^-6 = [OH-] pOH = -log 3.6x10^-6 = 5.44 pH = 8.6 (note the pH is alkaline, as expected)
NaF stands for sodium fluoride.
Naf is not in the Oxford English dictionary.
It is a strong base.
It is a strong base.
It is a strong base.