Yes; it is an intermolecular bond between a metal (in this case Sodium, or Na) and a nonmetal (Iodine, or I), which is an ionic bond.
0
2 Neutrons, WHY? NA=NOTHING 1=1 YES? The own neutron it is in = 1 the plus 1+1 = 2 neutrons
Sodium, Na, is a group 1 element and generally holds a +1 charge.
That is a list of the valences of several elements.Hydrogen is +1 (and also -1, incidentally)Sodium is +1Potassium is +1Calcium is +2
13
-1
The ion for Potassium has a charge of 1+.The ion for Iodine has a charge of 1-.This means that in order to make the overall charge of a unit of a compound of Potassium and Iodine, there must be one atom of Potassium and one atom of Iodine.Therefore, when K+ and I- are bonded, they make the ionic compound of KI.
Because sodium is a Group 1 metal and iodine is a Group 17 nonmetal, they will form an ionic bond to form the ionic compound NaI, called sodium iodide. The sodium atom will lose one electron to the iodine atom, forming a Na+ ion and an I- ion. The ions of opposite charge will form an electrostatic attraction called an ionic bond.
+1
Na+1 NO3- => Na(NO3)
This is called an ionic bondExample:Na --> Na+ + 1 e-Cl + 1 e- --> Cl-Na+ + Cl- --> Na+Cl-
+1 for Na, -2 for each O, +7 for Iodine
0
2 Neutrons, WHY? NA=NOTHING 1=1 YES? The own neutron it is in = 1 the plus 1+1 = 2 neutrons
Yes, Schottky defects are created when equal number of cations (Na+) and anions (Cl-) are missing from some ionic compound, since they have single charges (= equal, = 1 as absolute value)
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The ion for Potassium has a charge of 1+.The ion for Iodine has a charge of 1-.This means that in order to make the overall charge of a unit of a compound of Potassium and Iodine, there must be one atom of Potassium and one atom of Iodine.Therefore, when K+ and I- are bonded, they make the ionic compound of KI.