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prove that d (x1,xn)<=d (x1,x2)+d (x2,x3)+.................+d (xn-1,xn)

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Q: Is compact metric space is complete?
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Related questions

Is Closed and bounded subset of a complete metric space compact?

No.


When is a metric on a set complete?

A metric on a set is complete if every Cauchy sequence in the corresponding metric space they form converges to a point of the set in question. The metric space itself is called a complete metric space. See related links for more information.


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The question doesn't make sense, or alternatively it is true by definition. A Hilbert Space is a complete inner product space - complete in the metric induced by the norm defined by the inner product over the space. In other words an inner product space is a vector space with an inner product defined on it. An inner product then defines a norm on the space, and every norm on a space induces a metric. A Hilbert Space is thus also a complete metric space, simply where the metric is induced by the inner product.


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No. Every infinite dimensional topological vector space is not locally compact. See the Wikipedia article on locally compact spaces.


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