The empirical formula is similar.
C2H4O2=molecular formula, basically you multiply the empirical formula by 2.
Yes, it LOOKS like an empirical formula BUT it is NOT a correct one:Either C9H20 or C8H18 are correct (both are saturated alkanes) but not C8H20
The acetic acid is C2H4O2. It is often written has CH3CO2 to distinguish it from its isomers.
Vinegar is highly diluted acetic acid. Acetic acid has the molecular formula of C2H4O2. The structural formula for acetic acid is CH3COOH
60.04
Empirical formula is a useless notion; important is the molecular formula.
This is an empirical formula - a formula without indication about the structure of the molecule.
C2H4O2=molecular formula, basically you multiply the empirical formula by 2.
C2H4O2 normally written as CH3COOH to show the presence of the carboxyic acid group
C12h24
Yes, it LOOKS like an empirical formula BUT it is NOT a correct one:Either C9H20 or C8H18 are correct (both are saturated alkanes) but not C8H20
yes i can answer it
C2h4o2 is the molecular formula for CH2O.
CH3COOH Or if you like... C2H4O2
There are numerous compounds with this ratio. The simplest of them is formaldehyde with the formula CH2O. More complex molecules with more atoms but the same ratio include acetic acid (C2H4O2), lactic acid (C3H6O3), and glucose and its isomers (C6H12O6).
expanded Formula: CH3COOH, condensed Formula: C2H4O2
The acetic acid is C2H4O2. It is often written has CH3CO2 to distinguish it from its isomers.