Physics

Electronics Engineering

# Is kirchoff's voltage law applicable for an open circuit?

###### Wiki User

###### July 09, 2009 2:15PM

kirchoffs voltage law is appliciable for an open circuit when a diode/transister is higher or greater than the voltage and then divide it by the reistance!

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### Why kirchhoff's voltage law is applicable for open circuit?

Kirchoff's Voltage Law does not work, per se, for open circuits.
You need a closed circuit for it to make any kind of sense.
The signed sum of the voltage drops going around a series
circuit is equal to zero.
That means you have a closed circuit.
However, it can be argued, correctly, that an open circuit is
simply one that has two nodes with infinite resistance between
them. Assuming that all of the other nodes have something less than
infinite resistance between them, then Kirchoff's law does work, of
sorts, in that the voltage drop across all nodes that are not
voltage sources will be zero, because there is no current, and the
voltage drop across the two nodes with infinite resistance will be
equal to the sum of the voltage rises across the voltage sources.
Current sources in such a circuit will not work, because, with zero
current, they would attempt to generate infinite voltage.
Answer
Kirchhoff's Voltage Law does indeed apply to an open
circuit, because the voltage drop across the open part of the
circuit is numerically equal to the supply voltage and, hence, the
algebraic sum of the voltage drops around that particular loop is
zero.
Kirchoff's Voltage Law does not work, per se, for open circuits.
You need a closed circuit for it to make any kind of sense.
The signed sum of the voltage drops going around a series
circuit is equal to zero.
That means you have a closed circuit.
However, it can be argued, correctly, that an open circuit is
simply one that has two nodes with infinite resistance between
them. Assuming that all of the other nodes have something less than
infinite resistance between them, then Kirchoff's law does work, of
sorts, in that the voltage drop across all nodes that are not
voltage sources will be zero, because there is no current, and the
voltage drop across the two nodes with infinite resistance will be
equal to the sum of the voltage rises across the voltage sources.
Current sources in such a circuit will not work, because, with zero
current, they would attempt to generate infinite voltage.
Read more:
http://wiki.answers.com/Why_kirchhoff's_voltage_law_is_applicable_for_open_circuit#ixzz1i2fWNqfN