The compound NaHCO3 is also known as Sodium bicarbonate this often appears in very fine powder like baking soda. It has can be lactose that is found in milk to considered to be soluble with NaHCO3.
Decanoic acid is soluble in NaOH solution.
Yes.
Lactose is a monosachcharide.They are soluble in water.
NaHCO3 is sodium bicarbonate (baking soda.) It is water soluble, and in solution it will dissociate into Na+ ions and HCO3- ions.
Several part problem. Get molarity of NaHCO3. (150 ml)( M NaHCO3) = (150 ml)(0.44 M HCl) = 0.44 M NaHCO3 --------------------------- get moles NaHCO3 ( 150 ml = 0.150 Liters ) 0.44 M NaHCO3 = moles NaHCO3/0.150 Liters = 0.066 moles NaHCO3 ---------------------------------------get grams 0.066 moles NaHCO3 (84.008 grams/1 mole NaHCO3) = 5.54 grams NaHCO3 needed ---------------------------------------------answer
NaHCO3 Commonly called Baking Soda.....
All you need is the moles and the mass of NaHCO3 and you have the moles 0.025 moles NaHCO3 (84.008 grams/1 mole NaHCO3) = 2.1 grams of sodium bicarbonate ---------------------------------------------
Yes, lactose soluble is NaOH. Sodium is Na always and is water soluble. The website Study Mode has many examples of experiments done to prove that lactose is soluble.
Lactose is a monosachcharide.They are soluble in water.
NaHCO3 is sodium bicarbonate (baking soda.) It is water soluble, and in solution it will dissociate into Na+ ions and HCO3- ions.
When NaHCO3 plus HCL reacted they forum two different substance that is H4CO3+NaCl, That is the balanced formula.
Monsaccharides are a simple for a sugar and can have a sweet taste. They are usually colorless and water-soluble. Monosaccharide includes glucose and galactose. Lactose is made from both of those at its simplest forms.
Several part problem. Get molarity of NaHCO3. (150 ml)( M NaHCO3) = (150 ml)(0.44 M HCl) = 0.44 M NaHCO3 --------------------------- get moles NaHCO3 ( 150 ml = 0.150 Liters ) 0.44 M NaHCO3 = moles NaHCO3/0.150 Liters = 0.066 moles NaHCO3 ---------------------------------------get grams 0.066 moles NaHCO3 (84.008 grams/1 mole NaHCO3) = 5.54 grams NaHCO3 needed ---------------------------------------------answer
Sodium bicarbonate (NaHCO3) is soluble in water; calcium carbonate (CaCO3) is practically insoluble in water.
5 M NaHCO3
The answer is NaHCO3
Divide 6.10 (g NaHCO3) by 84.007 (g.mol−1 NaHCO3) to get 0.0726 mol NaHCO3
The ratio of NaHCO3 to WHAT!
what does nahco3 make up