no, u start w/ ur known which is hydrogen always +1, now your 2nd iffy known oxygen is -1 so carbon can balance with -1
Graphite is pure carbon.So it has 0 oxidation state.
The oxidation number of carbon in ethane (C2H6) is -3. This is because hydrogen is assigned an oxidation number of +1, and since the molecule is neutral, the sum of the oxidation numbers must be zero.
The oxidation number of carbon in COCl2 is +2. In this compound, oxygen has an oxidation number of -2, and chlorine has an oxidation number of +1. Since the overall charge of COCl2 is zero, the oxidation number of carbon must be +2 to balance out the charges.
In CH2Br2, carbon has an oxidation number of -2 because hydrogen has an oxidation number of +1 and bromine has an oxidation number of -1. The sum of the oxidation numbers in a neutral compound is zero.
The oxidation number of carbon in CH3-CH2-OH can be calculated using the formula: sum of oxidation numbers of all atoms in a neutral compound is zero. In this case, the oxidation number of carbon in CH3-CH2-OH is -2.
The sum of oxidation states in a neutral compound is zero. In glucose (C6H12O6), carbon is the most electronegative element and has an oxidation state of -4 (H=+1, O=-2). With six carbon atoms, each with an oxidation state of -4, the total oxidation state for carbon is zero.
Graphite is pure carbon.So it has 0 oxidation state.
The oxidation number of carbon in ethane (C2H6) is -3. This is because hydrogen is assigned an oxidation number of +1, and since the molecule is neutral, the sum of the oxidation numbers must be zero.
The oxidation number of carbon in COCl2 is +2. In this compound, oxygen has an oxidation number of -2, and chlorine has an oxidation number of +1. Since the overall charge of COCl2 is zero, the oxidation number of carbon must be +2 to balance out the charges.
In CH2Br2, carbon has an oxidation number of -2 because hydrogen has an oxidation number of +1 and bromine has an oxidation number of -1. The sum of the oxidation numbers in a neutral compound is zero.
The oxidation number of carbon in CH3-CH2-OH can be calculated using the formula: sum of oxidation numbers of all atoms in a neutral compound is zero. In this case, the oxidation number of carbon in CH3-CH2-OH is -2.
The oxidation number of oxygen in carbon suboxide is -1. In carbon suboxide, C3O2, the carbon atom has an oxidation number of +4, while the two oxygen atoms each have an oxidation number of -1 to give a total charge of zero for the molecule.
The oxidation number of carbon in carbon dioxide (CO2) is +4. This is because oxygen typically has an oxidation number of -2, and since there are two oxygen atoms bonded to the carbon atom in CO2, the carbon atom must have an oxidation number of +4 to balance the charge.
The oxidation number of carbon in hydrogen carbonate (HCO3-) is +4. This can be determined by considering the oxidation numbers of the other elements in the compound (hydrogen and oxygen) and applying the rule that the sum of oxidation numbers in a compound must equal zero.
The oxidation number of carbon (C) in CH2O is +2. This is because hydrogen (H) has an oxidation number of +1 and oxygen (O) has an oxidation number of -2, so the sum of the oxidation numbers in CH2O must be zero to balance the charge.
The oxidation number of carbon in C2H4 is -3. This is because each hydrogen atom has an oxidation number of +1, and the overall molecule has a net charge of 0. The sum of the oxidation numbers in a neutral compound must equal zero.
The oxidation state of carbon in formaldehyde (CH2O) is +2. This is because oxygen typically has an oxidation state of -2, and there are only two atoms of oxygen present in formaldehyde. The overall charge of formaldehyde is zero, so the sum of the oxidation states must equal zero, leading to carbon having an oxidation state of +2.