it is maximum at the poles
Solar maximum can occur up to 42 degrees north of the equator as it did in 1859.
A pendulum will swing slowest when closest to the equator. Why is this? The time period, T, of the swing of a pendulum is given by: T=2π√(l/g) where l is the length of the pendulum and g is acceleration due to gravity. Because the Earth is spinning, there is a bulge at the equator and the poles are slightly flattened. Hence on the equator the radius to the centre of the earth is greater than the radius at the poles. The equatorial radius is 6378.1km while the polar radius is 6356.8 km The value of g at the Earth's surface relates to the values of the Earth's radius, r, at that point using an inverse square law ie g is proportional to 1/r2 At the North Pole, g is about 9.83m/s2, while at the equator, g is smaller, at only 9.79m/s2 . So the period of a pendulum will be longer (i.e. slowest) at the equator than at the pole
roughly 23.5 degrees north or south of the equator
The Equator is the latitude line with a given value of 0-degrees. There Equator runs completely around the Earth. There are 360-longitude lines that intersect the Equator.
Maximum inclination of moon's orbit to the ecliptic = 5.3°Current inclination of the ecliptic to the celestial equator = 23.4°Moon's maximum declination = 5.3° + 23.4° = + 28.7°Maximum altitude of the celestial equator at 42° north latitude = 90° - 42° = 48°Moon's maximum altitude at 42° north latitude = 48° + 28.7° = 76.7°
at the poles
it is greater at poles than equator
we know g equalls GM/R*R. Therefore g is inversly proportional to R spuare. Where R is radius of the planet. The R at the equator is the greatest. Hence the value of g is min at the equator. The value if g increases from the equator to the poles.
The value of g depends on latitude because the Earth is wider at the equator than at the poles. g = 9.80612 - 0.025865 cos (2 x latitude) metres/sec/sec It expresses how quickly an object accelerates after being dropped. The formula gives 9.7802 at the equator and 9.8320 at the poles. The weight of a 1 kg mass is g Newtons.
Solar maximum can occur up to 42 degrees north of the equator as it did in 1859.
value of acceleration due to gravity is maximum at the surface of earth. So the gravitational field strength. as g'=g(1-d/R) at surface d=R so d=R so g'=g at earth's centre g=0. Its value decrease with decrease or increase in height. as: g'=g(1-2h/R) ......for height h and g'=g(1-d/R) .....for depth d
Gravitational potential is maximum at poles.
What is maximum value
The acceleration of gravity (value of 'g') is maximum on the earth's surface, and it decreases from there in both directions ... up into the air or down into the earth.
On Earth:Do you mean acceleration due to gravity?Here is your answer minimum value of g=9.8m/s2maximum value =10m/s2 approximately.Elsewhere:Anything positive and finite is theoretically possible.
g will increase when rotation is stopped because:- g depend on following thing;:- first on shape of earth second on rotation....(only Equator) not pole third one on going altitude and depth,...........
the equator