When aluminum burns, the reaction is highly exothermic.
The formation of aluminum oxide is highly exothermic. The correct reaction equation is 6 Al plus 3 O2 equals 3 Al2O3, however.
exothermic
Exothermic
4Al + 3O2 ---> 2Al2O3
The ionic compound Al2O2 forms when aluminum reacts with oxygen.
Aluminium + Oxygen ----> Aluminium oxideBalanced equation:4 Al + 3 O2 ----> 2 Al2O3
It is a synthesis reaction because the two substances are combining to form one.
The balanced chemical equation for the reaction between Al and O2 is: 4Al + 3O2 -> 2Al2O3 Therefore, the coefficient needed for Al to balance the equation is 4.
This is a synthesis reaction, and when it's balanced, it looks like this: 4Al + 3O2 --> 2Al2O3
4Al + 3O2 ---> 2Al2O3
2Al2O3 --> 4Al + 3O2
4Al + 3O2 -> 2Al2O3
4Al+3O2-->2Al2O3
The ionic compound Al2O2 forms when aluminum reacts with oxygen.
Aluminium + Oxygen ----> Aluminium oxideBalanced equation:4 Al + 3 O2 ----> 2 Al2O3
It is a synthesis reaction because the two substances are combining to form one.
4Al(s) + 3O2(g) --> 2Al2O3(s) where Al has an oxidation number of 3+
The balanced chemical equation for the reaction between Al and O2 is: 4Al + 3O2 -> 2Al2O3 Therefore, the coefficient needed for Al to balance the equation is 4.
4Al(s)+3O2(s) - > 2Al2O3(s)
No. If you mean 4Al3O2. And If you mean 4Al + 3O2 ------> AL2O, it is still not balance.