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Answered 2011-06-13 14:14:03

There is no such pair.

The solution to equation 1 and equation 2 is x = 1, y = 1.

The solution to equation 2 and equation 3 is x = 1, y = 1.

And the solution to equation 1 and equation 3 is any point on the line 3x + 2y = 5 - an infinite number of solutions.

The fact that the determinant for equations 1 and 3 is zero (or that they are not independent) does not mean that there is no solution. It means that there is no UNIQUE solution. In this particular case, the two equations are equivalent and so have an infinite number of solutions.

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That means there is no solution.There is no set of numbers that you can assign to the variables in the system of equationsthat will make '2' equal to '0'.

It is used for solving a system of linear equations where the number of equations equals the number of variables - and it is known that there is a unique solution.

You have two unknown variables, x and y. You therefore need at least two independent equations to find a solution.

They are two equations in two unknown variables (x and y), which are inconsistent. That is to say, there is no simultaneous solution. An alternative approach is to say that they are the equations of two lines in the Cartesian plane. The lines are parallel and so they do not meet indicating that there is no simultaneous solution.

It is a linear equation in two variables representing a line in the Cartesian plane. Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.

When (the graph of the equations) the two lines intersect. The equations will tell you what the slopes of the lines are, just look at them. If they are different, then the equations have a unique solution..

They both: - have variables, - are open sentences, - consist of two expressions joined by a "verb" (equals or inequality sign), - have solution sets (which may be empty or have one or more elements).

Roughly speaking, to get a unique solution - or at least, a limited number of solutions - if you have 3 variables, you need 3 equations, not just 2. With the two equations, you can get a relationship between the three variables, but not a unique value for a, b, and c. To get the general relationship, solve both equations for "c", replace one in the other, and solve the resulting equation for "a" to get the relationship between the variables "a" and "b". Then, for any valid combination of values for "a" and "b", use the simpler of the original equations (a + b + c = 24) to get the corresponding value for "c".

That is NOT a "system of equations". That is an equation. There is no solution to that, but it is a line with a y-intercept of -2, and a slope of -3.

Is an equation of a straight line in 3 dimensions. It cannot be simplified further, and a solution for any of the variables requires another two [independent] equations.

Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.

Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.

When talking about a "system of equations", you would normally expect to have two or more equations. It is quite common to have as many equations as you have variables, so in this case you should have two equations.

You need three independent equations to solve for three unknown variables.

It's an inconsistent pair of equations, for which there is no solution.

Because this equation has four variables, it would require four unique equations involving only these four variables to solve.

A pair of simultaneous equations in two unknowns which are inconsistent - in the sense that there is no solution that simultaneously satisfies both equations. Graphically, the equations are those of two parallel lines (slope = 2). Since, by definition, they cannot meet there is no solution to the system.

That system of equations has no solution. When the two equations are graphed, they turn out to be the same straight line, so there's no such thing as a single point where the two lines intersect. There are an infinite number of points that satisfy both equations.

In the equations Y=X-1 and Y=-X+1, the solution is (1,0)

The answer is that it cannot be done. To solve a set of equations in k variables (in this case, 2) you need at least two independent equations.

Since your equation has two variables in it ( 'x' and 'c' ), a "solution" is a number for each of themthat makes the equation true.Sure, if you want 'x' to be 3, I can figure out what 'c' has to be.And if you want 'c' to be 3, then I can figure out what 'x' has to be.But the "solution" is a pair of numbers that tells you what they BOTH have to be.And in order to figure that out for two variables, you need two equations.

x = 3, y = 9 is one solution from infinite number of find another solution just choose any number for x, substitue it in the equation, for example if x = 1, y= 4 * 1 - 3 = 1, so 1 and 1 is another solution for y = 4 x - 3In this question there is only one equation which contains two variables, so there is no unique solution.we need other independent equation contains the variables x and y then we can solve these equations simultaneously, i.e. we can find finite number of solution (its one solution in linear equations)

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