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Using the formula s = ut + 1/2at2, where s is the distance travelled, u is the initial velocity, a is the acceleration and t is the time , then :-

s = 0 + [1/2 x 9.8 x (9.36)2] = 429.29 meters (2dp)

The cliff is 429.29 meters high.

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Q: Item is dropped off a cliff Gravity immediately grabs hold of it at 9.8 meters per second squard Impact is 9.36 seconds How high is the cliff in meters Assume no air resistance?
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