For this you need the atomic mass of Fe. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.
82.5 moles Fe / (55.9 grams) = 1.48 moles Fe
7.4 moles iron (55.85 grams/1 mole Fe) = 413.29 grams iron
0.10 moles iron (55.85 grams/1 mole Fe) = 5.6 grams of iron ==============
1.68 grams iron (1 mole Fe/55.85 grams) = 0.030 moles iron ==============
A mole of an element is X grams of the element, where X is the number of the elements atomic mass. The atomic mass of iron is 55.85, so one mole of iron is 55.87 grams. Two moles of iron is 111.7 grams. 101.7 grams is 101.7/55.85 moles = 1.82 moles.
The answer is 0,2686 moles.
23 grams iron ( 1mole Fe/55.85 grams) = 0.41 moles of iron
8200 grams iron (1 mole Fe/55.85 grams) = 146.8 moles iron ============
738 grams iron are equivalent to:- 12,626 moles- 76.10e23 atoms
Let's see. 3 moles gold (197.0 grams/1 mole Au) = 591 grams of gold ----------------------------- 10 mole iron (55.85 grams/1 mole Fe) = 558.5 grams of iron ----------------------------- So, 3 moles of gold has more mass that 10 moles of iron. (heavier)
111.8g/55.8g= 2.004 moles
The rusting of iron has the reaction 4 Fe + 3 O2 equals 2 Fe2O3. So every 2 moles of iron produces 1 moles of iron oxide. 16.7 grams is .299 moles of iron. This means there are 0.149 moles of iron oxide or 23.88 grams.
75.89 grams of FeO is equal to 1.06 moles of iron II oxide. In decomposition, there would be 1.06 moles of iron recovered, or 58.99 grams.
2.56 X 10^-3 moles iron (55.85 grams/1 mole Fe) = 0.143 grams of iron
Fe, or iron, has a molar mass of 55.845 grams per mole. This means that 0.2 moles is equal to 11.2 grams of iron.
To calculate the number of moles from grams, you must divide by the substance's molar mass
1,25 g of anhydrous iron(III) nitrate = 0,005 moles
200 grams Fe (1 mole Fe/55.85 grams) = 3.58 moles of iron --------------------------
2 moles of iron is equal to 111,69 g.
This cannot be answered because it is essential to know what element you're dealing with here. 8.2 grams of iron will contain considerably less atoms than 8.2 of hydrogen. Therefore, the number of moles in 8.2 grams of iron will differ from the number of moles in 8.2 grams of hydrogen.
150.0 grams Fe2O3 (1 mole Fe2O3/159.7 grams) = 0.9393 moles or iron(III)oxide
825 grams = 825,000 mg. 1 gr. = 1000 mg.
Find iron (Fe) on the periodic table the biggest number (at the bottom) is the mass number 1 mole is that number in grams. you can work it out from there.
25 grams Fe2O3 (1 mole Fe2O3/159.7 grams) = 0.16 moles iron (III) oxide ( Ferric oxide ) ==============================
Moles is equal to grams divided by the mw therefore grams=(mw)(moles).
Iron (III) oxide -> Iron + OxygenSteps to find the mass of iron obtained from 268g of iron (III) oxide:Step 1: Write the balanced equation2Fe2O3 -> 4Fe + 3O2Step 2: Identify key reactants and products2Fe2O3 -> 4FeStep 3: Write down the mole ratio2 moles : 4 molesStep 4: Change moles into gram formula mass2((2x56)+(3x16)) : 4(1x56)320g : 224gStep 5: Find out how many grams of iron will be produced for every gram of iron (III) oxide1 gram = 224/320 = 0.7gStep 6: Find out how many grams of iron will be produced for 268 grams of iron (III) oxide268 grams = (224/320)x268 = 187.6 gramsThe mass of iron produced from 268 grams of iron (III) oxide is 187.6 grams.