The product is sodium chloride.
The reaction is:
NaOH + HCl - NaCl + H2O
HCl + NaOH --> NaCl + H2O
(acid) + (base) --> (salt) + (water)
NaCl and water?
HCl + NaOH -------> NaCl + H2O
HCl+NaOH-->NaCl +H2O
HCl + NaOH = H20 + NaCl
This is a neutralization reaction.
NaOH and HCl
HCl is an acid which reacts with NaOH a base to produce H2O water and a salt - in this case NaCl HCl + NaOH = NaCl + H2O
HCl + NaOH -----> NaCl + H2O
The reactants are HCl and NaOH.
The reactants are NaCl and H2O. A becks: HCl NaOH
NaOH and HCl
HCl is an acid which reacts with NaOH a base to produce H2O water and a salt - in this case NaCl HCl + NaOH = NaCl + H2O
HCl + NaOH -----> NaCl + H2O
The reactants are NaCl and H2O. A becks: HCl NaOH
The reactants are HCl and NaOH.
Balanced equation. NaOH + HCl -> NaCl + H2O all one to one. find moles HCl. 11 grams HCl (1 mole HCl/36.458 grams ) = 0.3017 moles HCl Moles HCl same as moles NaOH Molarity = moles of solute/Liters of solution 1.06 M NaOH = 0.3017 moles NaOH/liters of solution = 0.2846 Liters this is equal to..... 285 milliliters of NaOH needed
1 HCl + 1 NaOH ---> 1 NaCl + 1 H(OH)
That is correct: HCl(aq) + NaOH(aq) --> NaCl(aq) +H2O
The reaction between HCl and NaOH is a neutralization reaction, or an acid/base reaction. It isHCl + NaOH ==> NaCl + H2O
The chemical equation is: NaOH + HCl = NaCl + H2O
HCl+NaOH, when mixed in equimolar amounts, produces a neutral solution of NaCl.
TiOCl2 + NaOH - TiO2 + NaCl + HCl