Commutivity of multiplication or the commutative property of multiplication.
The generalisation is that multiplication is Abelian (or commutative) for numbers.
1x15 3x5 5x3 15x1
All of them. 1x15,2x7.5, 3x5, 4x3.75, 5x3...
since 15 = 3x5 and 75 = 3x5x5 H.C.F = 5X3 = 15 !
seventeen over fifteen because the common denominator of 5 and 3 is 15 think about it like this: 4/5x3, 4x3=12, 5x3=15 1/3x5, 1x5=5, 3x5=15 so you get 12/15+5/15 see how they simplify back? then add the numerators and keep the denominator and you get 17/15 or 1 and 2/15
If you're asking what x equals, it equals 5 because 5x3=15, and 15-2=13.
3/5 - 1/3 = (3x3)/(5x3) - (1x5)/(3x5) = 9/15 - 5/15 = 4/15
Since 5x is a factor of both terms, divide it. 5x3 + 5x = 5x(x2 + 1)
5x3 = 45x Divide both sides by 5: x3 = 9x Divide both sides by x: x2 = 9 Square root both sides: x = 3
3x+5=20 x=5 since 5x3+5=20
look its one of the easiest questions I've ever heard 5x3 is 15 for god sake anybody who dosent know that there one of the dummest person in the world!
y = 5x3 + 6 is a cubic equation, not a linear equation. Linear equations contain only terms of degree 0 (i.e. constants) and terms of degree 1.
None. 5x3 is a pure number, not a length.
Because the answer to 5x0.5 is 2.5 as the answer to 5x0.3 is 1.5 and 5x3 is 15.
15 5x3 prime factorization: 5x3
No. x=3. (5x3 is 15 or 5x =15-3=12)
5x3=4 2x8=2 6x3=3 1x7=7/40
y = 5x3 + 5 is a cubic equation. You cannot solve for x (or y), because there are two variables and only one equation. If you graph this, however, you will see a curve that passes through all possible points that make this equality true.
5x3 = 320 x3 = 320/5 = 64 So x = cuberoot(64) = 4
An expression. It can be factored out slightly too: 2x6 + 5x3 - 7x4 = x3(2x3 - 7x + 5)
If you meant the distributive property of mutiplication over addition.Example:5x(4+3)=35 or (5x4)+(5x3)=35. In general, for any numbers,a,b, and c this is true a(b + c)=a x b+a x c.
Coefficient -5. Base: x. exponent: 3. Value: depends on the value of x. or Base: (-5)1/3x, exponent: 3
3x4 plus 5x3 plus x2 - 5 divided by x 2 =[(3x4) + (5x3) + (x2 - 5)]/x2 =(12 + 15 + x2 -5)/x2 =(27 - 5 + x2)/x2 =(22 + x2)/x2
5x3 - 3x2 + 2x = x*(5x2 - 3x + 2) The quadratic has no real factors.
GCD is greatest common divisor.we will write numbers in the form of their multiples.so 75=5x5x390=5x3x3x2so we have (5x3) common in both. so the ans is 5x3=15 :-)