What is the oxidation number for S in S 2?

Answer 1

Pure element has zero oxidation number. When forming ions it is equal the charge of ion.

Atomic sulfur has oxidation number of 0. Its simple ion, sulfide carries oxidation status -2. While forming numerous compounds, the oxidation number of sulfur can vary form -2 to +6.

Answer 2

If your considering it on its own as an element then its oxidation state is 0 unless it is reacting with another element example would be Al +S (aluminum sulfide) Al is ^+3 and becasue sulfur is two elements to the noble gas Ar it has an oxidation numberis s^-2

and to write the correct formula for aluminum sulfide ( is monoatomic compound) the oxidation number must equal 0 so it will be Al 2 S 3 .

you assign oxidation number as follows

group 1a is +1 2a is + 2

and for the non metals subtract element from nearest noble gas becasue that is how many electrons it needs to become stable .....

Answer 3

That depends on the compound that it is in but it is often found in the oxidation states 2-, 4+, and 6+. In its elemental for the oxidation state is 0, which is true of all elements.

In sulfides, thiols, and similar compounds such as H2S, K2S, CH3SH and HSCN it s int the 2- oxidation state.

In sulfur dioxide (SO2) and sulfites such as Na2SO3 and SrSO3 it is in the 4+ oxidation state.

In sulfur trioxide (SO3), sulfuric acid (H2SO4), and sulfates such as MgSO4, K2SO4, and NaHSO4 it is in the 6+ oxidation state..

Answer 4

Pure element has zero oxidation number. When forming ions it is equal the charge of ion.

Answer 5

Atomic sulfur has oxidation number of 0. Its simple ion, sulfide carries oxidation status -2. While forming numerous compounds, the oxidation number of sulfur can vary form -2 to +6.

Answer 6

S in SO2 has an oxidation value of +4

Answer 7

-2 for sulphur ins S2- ion

Answer 8

+2