Oxidation number of sodium?
0 in elemental form and +1 in its compounds
The oxidation number of oxygen is -1 in all peroxides. Since Sodium peroxide is a neutral molecule, its net charge is zero. If we make its, its charge equation, then we get, 2*1 + 2x=0 (since oxidation state of sodium is always 1) =>2x=-2 =>x=-1. Here x is the oxidation number of oxygen in the sodium peroxide molecule.
In the formula NaBrO3, Oxygen will always have a -2 oxidation number. In this case the total number for oxygen in -6 because there are three oxygen atoms. Sodium will always have a +1 oxidation number therefore its total oxidation number is +1. The entire charge has to equal zero so taking what we have now: -6 and +1 we have a -5 left over. Therefore, Bromine must have a +5 oxidation number.
A metal and a nonmetal would form an ionic bond. In an ionic compound, a metal ion would have a positive oxidation number equal to its ionic charge. A nonmetal would have a negative oxidation number equal to its ionic charge. Examples: NaCl oxidation numbers: sodium has an oxidation number of +1, chloride has an oxidation number of -1. So the overall charge of NaCl is zero. CaCl2 oxidation numbers: calcium has an oxidation number…
Sodium ortho-arsenite, although the name is often shortened to sodium arsenite. It contains the AsO33- ion ortho-arsenite ion. Arsenic has oxidation number +3. Confusingly there is another compound NaAsO2 sodium meta-arsenite whose name is also shortened to sodium arsenite. This contains a polymeric meta-arsenite ion (AsO2-)n . Again arsenic has oxidation number of +3