A prime number is a number that has only two factors which are itself and one.

It is: B 31 is a prime number because it has only two factors which are itself and one

293 is a prime number, therefore the prime factorization of it would be 293, you cant do 293x1 because 1 is NOT a prime number therefore you cant do it because it wouldn't b a prime factorization that is your answer

6 is not a prime number b\c, it is divisible to 2 and 3

62 is not a prime number and you cannot get a relitavely prime number it either is a prime number or it isnt a prime number! The definition of a prime number is a number that can only be divided b itself and one. No other number 62 can be divided by 2 as well as itself and 1 so NO IT IS NOT A PRIME NUMBER even numbers tend not to be prime numbers because they can be divided by two the only even number that is prime is 2 because it can only be divided by itself and 1 I hope this helped!

yes b/c 1 is neither prime or composite

21 is not a prime.

C-prime is the dominant note in the song "Defying Gravity" in the musical "Wicked."Specifically, two stanzas are Elphaba's contributions to "Defying Gravity" in "Wicked." The notes of the first stanza are the same as those of the second. The following lists the notes sung by Elphaba in each of her two stanzas on the soundtrack of the original Broadway cast:C-prime, d-prime, f-prime (5 in succession), g-prime;C-prime, d-prime, f-prime (3), g-prime (2);A-prime (2), g-prime, f-prime, e-prime, f-prime, d-double prime (2), c-double prime;C-prime, b flat-prime, a-prime, g-prime, f-prime;C-prime, b flat-prime, a-prime, g-prime, f-prime, e-prime, d-prime;C-prime, b, c-prime, b, c-prime, g-prime, c-prime, c-prime, g;C-prime, b, c-prime, a, g (2);C-prime, b, c-prime, g-prime, c-prime, b, c-prime, c-double prime, b-prime, g-prime, c-prime (2), d-prime (2), c-prime;E-prime (3), d-prime, c-prime, g, c-prime;E-prime (2), d-prime, c-prime, b, g, a-prime, g-prime.

He was the 11th Prime Minister, since 1930 - 1935.

Any number of the form a*b^4 where a and b are different prime numbers, or c^9 where c is a prime, will have exactly 10 factors.

The second movement is tertiary form, following ABA (prime) form. It can further be divided as A B A (prime) a a (prime) b b (prime) b tr a a (prime) Coda (b prime) I vi IV vi Va I There's more there, but i hope this helps

Any number of the form n = a*b*c*d*e*f where a, b, c, d, e and f are different prime numbers. n has 26 = 64 factors in total, of which 1 is the number 1 (neither prime nor composite), 6 are prime, and the remaining 57 are composite.

A factor of a integer is an integer that divides the second integer into a third integer exactly; i.e. A is a factor of B if B/A is exactly C, where all of A, B and C are integers. A prime factor is a factor as above, but is also a prime number. This means that the only factors of that factor are one and the number itself; i.e. A is a prime factor of B if B/A is exactly C andthe only factors of A are 1 and A.

If √7 is rational, then it can be expressed by some number a/b (in lowest terms). This would mean: (a/b)² = 7. Squaring, a² / b² = 7. Multiplying by b², a² = 7b². If a and b are in lowest terms (as supposed), their squares would each have an even number of prime factors. 7b² has one more prime factor than b², meaning it would have an odd number of prime factors. Every composite has a unique prime factorization and can't have both an even and odd number of prime factors. This contradiction forces the supposition wrong, so √7 cannot be rational. It is therefore irrational.

Product of a prime number and a composite number results in a composite number.Now consider the product of a composite number(a) and a prime number(b) is equal to c.i.e. c = a x bIt is clear that c is divisible by both a and b.Also c is divisible by itself and 1, this means that c has more than two factors.A number having more than two factors is composite, therefore product of a prime number and a composite number results in a composite number.

Prime triple definition: Assume that a<b<c. a, b, and c form a prime triple just if both of the pairs (a,b) and (b, c) are twin primes.

Triple prime definition: Assume a<b<c. a, b, and c form a prime triple just if both the pairs (a, b) and (b, c) are twin primes.

Prime numbers only have two factors, one and themselves. If Player A picks the prime number, Player B gets the 1.

Proof by contradiction: suppose that root 7 (I'll write sqrt(7)) is a rational number, then we can write sqrt(7)=a/b where a and b are integers in their lowest form (ie they are fully cancelled). Then square both sides, you get 7=(a^2)/(b^2) rearranging gives (a^2)=7(b^2). Now consider the prime factors of a and b. Their squares have an even number of prime factors (eg. every prime factor of a is there twice in a squared). So a^2 and b^2 have an even number of prime factors. But 7(b^2) then has an odd number of prime factors. But a^2 can't have an odd and an even number of prime factors by unique factorisation. Contradiction X So root 7 is irrational.

In number theory, two integers a and b are said to be relatively prime, mutually prime, or coprime (also spelled co-prime) if the only positive integer that evenly divides both of them is 1. That is, the only common positive factor of the two numbers is 1.

B may be any prime number. The fact that C is at least 3A has no bearing on the limits of B.

B, as a variable, can stand for any number. The factor possibilities are infinite.

a and b have no common prime factors. Their LCM is their product.

It is likely that a, b and c are 2, 4 and 8. The prime numbers in that range are 11, 13, 17 and 19. D will be one of those, depending on that crucial bit of missing information: the sum of the numbers.

no idea, good questionAnswerB. Prime Minister

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