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I will prove a more general theorem from which your answer follows immediately. Theorem: The intersection of any number (including 2) of convex polygons is convex.

Proof

Let C be the intersection of Ci which is a set of iconvex polygons. By definition of intersection, if two points A and B belong to C then they belong to every one of the Ci . But the convexity of each of the Ci tells us that line segment AB is contained in Ci . Therefore, the line segment AB is in C and because ABwas arbitrary we conclude that C is convex

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0Well, It depends what kind of image do they want. It would be most likely a convex lens/ mirror. Convex lenses make things bigger.

Yes a intersection is any place where one line of traffic meets another. Another place where an intersection can occur is with lines in parking lots as well as on roadways.

Convex mirrors offer various advantages and are therefore, used in different equipment. They give a wide angle of vision as well as a large field of view.

It is used in set theory to indicate intersection. The intersection of two sets, A and B, is the set of all elements that are in A as well as in B.

A polygon is convex if it has no two points that can be used to define a line segment that falls outside of that polygon. Another way to put it is: a convex polygon has all vertices pointing 'out'. Consider the following 6-sided polygon: _ ' | |_ |__| Well you get the idea. The 'notch' cut out of the square turns the square into a six sided figure now, with the 'corner' in the upper right pointing 'in' so the polygon is not convex.

Well then you look at it and that is the persons fault. What do you mean?

Both union and intersection are commutative, as well as associative.

Your question makes no sense

well the thing is u cnt

well you see to prove who really is the murderer you have to prove whos' innocent

do something outrageous!!prove to him that you wouldn't lie about something like that!!how??well it depends on the situaution!

i guess it doesnt really matter. my magnifying glass is a convex lens so yaaaa. well that's all i got cuz this website don't even no what a concave or convex lens is.

Suppose A is a subset of S. Then the complement of subset A in S consists of all elements of S that are not in A. The intersection of two sets A and B consists of all elements that are in A as well as in B.

Well, there are lenses that help us see near and far. These are concave and convex. Concave lenses are curved inward on both sides (like a cave) and convex lenses have both sides curving outward. Concave make you see things smaller and convex make you see everything bigger.

This is really a version of deMorgans that states the complement of the intersection of any number of sets equals the union of their complements.We prove it in general and this is a specific case.Take x contained in the complement of the intersection of all sets Aj that is to say x is not in the intersection of all Aj . Now there must be at least one set that does not contain x since if all sets contain x then x would be in their intersection as well. Call this set A. Since x is not in A, x must be in the complement of A. But then x is also in the union of all complements of Aj , because A is one of those sets. This proves that the right hand set is contained in the left one.We now prove it the other way, that is to say, the left hand side is contained in the right. Remember that if A and B are sets and A is contained in B and B is contained in A we can say that as sets A=B.Consider x contained in the union of all complements of Aj . That means there is at least one complement that contains x, or in other words, at least one of the Aj does not contain x. But then x is not in the intersection of all Aj , and hence it must be in the complement of that intersection. That proves the other inequality, so both sets must be equal.

The reason people debate is to prove the point they are trying to prove. They are supporting an idea and want others to support it as well.

Well ask Mr harrison! duhhh! also maso rocks everyones socks

Well, you could try Groove, prove, or approve.

ok well, go to google.com and type in "what scientists were able to prove Democritus?" and u will always see it!

Well.... you can't really prove something doesn't exist, you can only prove it does. But, nobody has found or seen a pikmin outside the game.

well yeah you allways have to be a good sprot

not only to prove a hypothesis, but disprove it as well

well their is no episode to prove that

Light rays converge as well as diverge. it depends upon the type of lens or mirror you pass it through. A concave lens or a convex mirror diverges the light whereas a convex lens or a concave mirror converges the light rays!

he went into the bathroom and uhmm well dropped his trousers haha he had to prove that everything matched haha

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