There isn't enough information here. Available short circuit fault level can be given as a KVA value for different types of faults, but I assume the questioner is looking for a relationshiop between (transformer?) KVA and available short circuit current -
If my assumption is correct, there is no direct correlation without knowing the transformer positive and zero sequence impedances. If these are known, you can assume the source impedance is infinite, and calculate the maximum short circuit current through the transformer as follows:
lowside fault current for a 3 phase fault on the lowside of the transformer:
lowside kV (line to line) / (1.732 x per unit positive sequence impedance x scalar to real impedance),
where scalar to real impedance is equivalent to lowside kV (line to line) ^2 / base kVA.
For a L-G fault, do the same with zero sequence impedance.
kvar can be calculated as follows the a product KVA andt the sine of the angle between the KVA and KW.
1.035 KVA
You can't determine the output voltage of a transformer by knowing kva. Transformers will be marked as to input and output voltages. Some will have multiple input and output voltages. The output voltage depends on the ratio of coil turns between input and output.
635kva
Va=volts x amps. The K stands for one thousand. So 1 Kva is one thousand watts. So 415v times 120a= 49,800 what's. You divide that by a thousand and you get 49.8. So it would be 49.8 Kva.
When the power factor is leading, the capacitive kVAr is more than the Inductive kVAr and this still has to be supplied by the source. As kVA is the vector sum of kW and kVAr, still for the given kW, you have to produce more kVA. Alternately, for the given kVA, you can only convert partially into useful work. Secondary effects are voltage boost in the system, availability of stored energy to feed the fault in case of a fault, increase in the asymmetrical component of fault current, increasing thus the peak value of the fault current, etc.
kvar can be calculated as follows the a product KVA andt the sine of the angle between the KVA and KW.
The 3 kVA transformer will weigh double the 1.5 kVA transformer.
kvar can be calculated as follows the a product KVA andt the sine of the angle between the KVA and KW.
kVA = kW divided by (power factor). The power factor is the cosine of the angle between voltage and current.
You don't calculate the rated kV.A of a circuit breaker; it's determined by the manufacturer. It's important that a circuit breaker's rated kV.A exceeds the fault level kV.A at the point where the circuit breaker is located, otherwise it may fail to interrupt a fault current and, possibly, self destruct.
For normal power factors (pf=80%), you have 0.8 kW for every kva. In general however, kW = pf x kVA. Where pf is the power factor, it is the cosine of the angular difference between the voltage and the current of a circuit in alternating current circuits.
P=1.73xVxIxCOSO KVA=KW/1.73xCOSO KVA=2000/1.4 KVA=1.42
1.035 KVA
You can't determine the output voltage of a transformer by knowing kva. Transformers will be marked as to input and output voltages. Some will have multiple input and output voltages. The output voltage depends on the ratio of coil turns between input and output.
min: 0.5 KVA MAX: 1.5 KVA
kva and kw are related as KVA = (KW/PF) pf:power factor