Comparision between motorola6800 And Intel 8086
Intel 8088 Intel 8086 Intel 286 Intel 386 Intel 486 Intel Pentium Intel Pentium II Intel Pentium III Intel Pentium IV Intel Itanium Motorola 6800 Zilog Z80
in 8085 only one accumulator used where in 6800 used two accumulator.
Robert J. Simpson has written: 'Introduction to 6800/6802 microprocessor systems' -- subject(s): Motorola 6802 (Microprocessor), Microcomputers, Motorola 6800 (Microprocessor) 'Advanced 8-Bit Microprocessor: Mc6809' 'A study of phase advance networks for a.c. control system stabilisation'
2 percent of 6800 = 136 = 2% * 6800 = 2%/100% * 6800 = 0.02 * 6800 = 136
Two numbers with a difference of 5 have a product of 6800. x and (x + 5) are our numbers. Let's multiply them together. (x) (x+5) = x2 + 5x That is equal to the 6800 specified. x2 + 5x = 6800 >> x2 + 5x - 6800 = 0 (x + 85) (x - 80) = 0 x + 85 = 0, so x = -85 (this in not a correct answer - it has the wrong sign) x - 80 = 0, so x = 80 (a correct answer, and one of the two numbers we need) Since x = 80, x + 5 = 85 Our numbers are 80 and 85. Let's check. 80 times 85 = 6800. Our work checks.
6800
Jack E. Hemenway has written: 'RA6800ML' -- subject(s): Assembling (Electronic computers), Motorola 6800 (Microprocessor), Programming, RA6800ML
6800
The Intel865G is integrated graphics meaning it is part of the motherboard. This type usually comes with low end computers and will be very limited as to what games it can play. The 6800 is a separate card that plugs into the motherboard and will provide grater graphics power. However, this is still not a very powerful card so if you with to play current games on it, you will need something better such as the Nvidia 8800 series or the 4XXX series from ATI. Their current top end model is the 4870 x2
6600, 6700, 6800, 6900 inclusive 6700 and 6800 exclusive
17% of 6800 = 6800*17/100 = 1156
31% of 6,800= 31% * 6800= 0.31 * 6800= 2,108