since we know that the total pressure is 670 mmhg and the pressure of water at 20 c is 17.5 mmhg, we use dalton's law.
670=17.5+ gas pressure
652.5=gas pressure by definition
then we use the law P1V1T2=P2V2T1
tp find V2=47.9969 L
The gas would occupy 40 liters of space, by volume. This is only true as long as the conditions were normal.
Assuming pressure is constant, like you said, volume and temperature have a direct relationship. As temperature increases, volume increases; as temperature decreases, volume decreases. Setting up a algebraic direct proportion, you get approximately 3.84 liters for the balloon at 285 degrees K.
Assuming no change in temperature and pressure, calculate the volume of O2 (in liters) required for the complete combustion of 14.9 L of butane (C4H10):
At STP, 1 mole of gas occupies a volume of 22.4 liters. Thus, 4/5 moles of gas will occupy .8*22.4 liters.
At STP, 1 mol or 6.02x10^23 representative particles, of any gas occupies a volume of 22.4 Liters. (chemistry)
The gas would occupy 40 liters of space, by volume. This is only true as long as the conditions were normal.
The volume of one mole of gas at a standard temperature and pressure is 22.4 liters. Multiply 22.4 liters by 0.25 moles to get a volume of 5.6 liters.
fly
It would be approx 9042 litres.
3.5 litre if pressure is kept constant.
Assuming pressure is constant, like you said, volume and temperature have a direct relationship. As temperature increases, volume increases; as temperature decreases, volume decreases. Setting up a algebraic direct proportion, you get approximately 3.84 liters for the balloon at 285 degrees K.
Of course. But at STP, any gas has a standard volume of 22.4 Liters.
Liters is a measurement of volume. 160 Liters is the volume.
54 liters at STP (standard temperature and pressure)
0.48 liters at STP (standard temperature and pressure)
Pressure and temperature. As pressure increases, volume decreases; as temperature increases, volume increases with it. At standard temperature and pressure (1 atm, 273 degrees Kelvin), one mole of a gas (6.022 x 1023 particles) has the volume of 22.4 liters.
Pressure and temperature. As pressure increases, volume decreases; as temperature increases, volume increases with it. At standard temperature and pressure (1 atm, 273 degrees Kelvin), one mole of a gas (6.022 x 1023 particles) has the volume of 22.4 liters.