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x + 4y = -14 eqn1
2x + 3y = 13 eqn2

Using the elimination method we multiply eqn1 by 2
2x + 8y = -28 eqn1b

Subtract eqn2 from eqn1b
2x + 8y = -28 eqn1b
2x + 3y = 13 eqn2
5y =-41
y = -8 and 1/5
substituting this into eqn1 we get

x +4 (-41/5) = -14
x = (14*5) / (41 *4)
x = (35/82)

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Q: Solve the system by the elimination method x plus 4y equals -14 and 2x plus 3y equals -13?
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