Sound intensity decreases when amplification (volume) decreases.
sound intensity decreases when what decreases
The amplitude of the sound waves decreases as the intensity decreases.
Yes.
Intensity
No, it follows the inverse square law. That is, the intensity is inversely proportional to the square of the distance. I2/I1 = (r1/r2)². Intensity decreases with 1/r² from increased distance, while the sound pressure decreases only with 1/r from increased distance.
Increase
The amplitude of the sound waves decreases as the intensity decreases.
Yes.
That means that it gets weaker.In physics, intensity is defined as power per unit area.
Intensity
That means that it gets weaker.In physics, intensity is defined as power per unit area.
No, it follows the inverse square law. That is, the intensity is inversely proportional to the square of the distance. I2/I1 = (r1/r2)². Intensity decreases with 1/r² from increased distance, while the sound pressure decreases only with 1/r from increased distance.
The speed of sound and density are related as . So the greater the density the speed of sound decreases.
As compared to what? - In general, if the sound energy spreads out over a larger area, the INTENSITY (power per cross-sectional area) decreases, since total energy must be conserved. (Of course, as some of the sound is absorbed, i.e. converted to other energy forms, the intensity decreases even more.)
because sound waves spread out, intensity decreases with distance from the source.
Sound intensity is a property of sound.
Sound intensity is inversely proportional to the square of the distancefrom the source.-- Increase the distance from the source by 10 times.-- Sound intensity decreases to 1/102 = 1/100 .-- 10 log ( 1/100 ) = -20 dB-- 100 dB - 20 dB = 80 dB
Sound intensity is mesured in decibels !