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Two points do not provide enough information to define a circle: a minimum of three points is required to uniquely define a circle unless one of the points happens to be the centre and the other is on the circle. In that case, however, it is necessary to know which is which.
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Is the equation for a circle a function?
The equation for a circle is a function in that it can be graphed and charted. One common equation is x^2 + y^2 = r^2.
The center of a circle is located at c(3-13). The x-axis is tangent to the circle at (30). Find the equation of the circle?
Equation of the circle: (x-3)^2 +( y+13)^2 = 169
What is the equation of a circle that passes through the points of 5 5 and 8 5 and 5 1 on the Cartesian plane showing work?
The points will form a right angle triangle in a circle whose hypotenuse is its diameterLength from (8, 5) to (5, 1) = 5Midpoint: (6.5, 3) which is the centre of the circleRadius: 2.5Equation of the circle: (x-6.5)^2+(y-3)^2 = 6.25
I have a maths question i dont get please help me!"Describe fully the graph which has the equation x² + y² = 16."?
It's a circle. The equation of a circle is x^2+y^2=r^2. So the equation you've given is a circle with a radius of 4 and, since there are no modifications to the x or y values, the center of the circle is located at (0,0).
Find an equation of the circle that has center 0 2 and passes through the origin.?
The equation of a circle with center (0,2) and radius r is x^2+(y-2)^2=r^2 Since it passes through (0,0) (the origin) 0^2+(0-2)^2=r^2 r^2=4 The equation of the circle is x^2+(y-2)^2=4
What is the standard form of the equation of a circle with its center at (2 -3) and passing through the point (-2 0)?
Points: (2, -3) and (-2, 0) Slope: -3/4 Equation: y = -0.75x-1.5
How do you write an equation in standard form of a circle with a center and radius?
The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2
What is the equation of the points (31) and has a radius length of 2?
If you mean a circle center at (3, 1) and a radius of 2 then the equation of the circle is (x-3)^2 +(y-1)^2 = 4
What is the equation of a circle whose diameter end points are at 8 7 and 2 -3 on the Cartesian plane?
End points: (8, 7) and (2, -3) Midpoint: (5, 2) which is the center of the circle Radius: square root of 34 Equation of the circle: (x-5)^2 +(y-2)^2 = 34
What is the equation of the points (-12) and has a radius of length 3?
If you mean a circle center at (3, 1) and a radius of 2 then the equation of the circle is (x-3)^2 +(y-1)^2 = 4
What is the standard equation of the circle?
Area of a circle = pi*radius squared Circumference of a circle = 2*pi*radius or diameter*pi
How do you Writing the Equation of a Circle in Standard Form?
(x - A)2 + (y - B)2 = R2 The center of the circle is the point (A, B) . The circle's radius is ' R '.
What is the standard equation of a circle with radius r centered at the point hv?
The equation is (x - h)2 + (y - v)2 = r2
What is the equation of the circle standard form?
Area of a circle = pi*radius squared Circumference of a circle = 2*pi*radius or diameter*pi
What is the standard equation for a circle that is centered at the origin with the radius r?
It is x^2 + y^2 = r^2
When you make the circle bigger or smaller which number of the standard equation for a circle centered at the origin changes?
Standard equation for a circle centred at the origin is x2 + y2 = r2 where r is the radius of the circle. If you increase the size of the circle then the radius must increase, so r2 will be larger. eg a circle of radius 2 has the equation x2 + y2 = 4, if the radius increases to 3 then the equation becomes x2 + y2 = 9
What is the Cartesian equation of a circle whose end points of its diameter are at 10 -4 and 2 2?
End points: (10, -4) and (2, 2) Midpoint: (6, -1) which is the centre of the circle Distance from (6, -1) to any of its end points = 5 which is the radius Therefore the Cartesian equation is: (x-6)^2 +(y+1)^2 = 25
