That would be a 5% solution of Lugol's iodine.
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
Reddish precipitate of Mercuric iodide and clear solution of Potassium chloride is produced
A yellow precipitate of silver iodide (AgI).
In aqueous solution they would not react. They would form a solution of ferric ions, chloride ions, potassium ions, and iodide ions.
Ag(NO3)(aq) + KI(aq) ---> K(NO3)(aq) + AgI(s)
somehow. the potassium iodide act as a acidifying agent,
A precipitate of Lead iodide and Potassium nitrate are formed
The solution of potassium iodide (if it is not extremely diluted) is more dense.
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
Reddish precipitate of Mercuric iodide and clear solution of Potassium chloride is produced
no
A yellow precipitate of silver iodide (AgI).
In aqueous solution they would not react. They would form a solution of ferric ions, chloride ions, potassium ions, and iodide ions.
Ag(NO3)(aq) + KI(aq) ---> K(NO3)(aq) + AgI(s)
Lead iodide (Pb2I) precipitates as a yellow solid, leaving a solution of potassium and nitrate ions.
It's the same thing. It is a solution of water that has been saturated to the max with potassium, then iodide is added (a form of iodine). So it is a potassium iodide solution.
KI or potassium iodide will be basic in solution because it is the product of KOH (a strong base) and HI (a weak acid.)