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Q: Suppose a rock is dropped off a cliff with an initial speed of 0 ms. What is the rocks speed after 5 seconds in ms if it encounters no air resistance?

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For conductor the resistance (R) is directly proportional to the length (L) of the conductor, and the area of cross-section (A). When you stretch the conductor to increase its length, its area of cross-section will decrease. The decrease in area of cross-section can be found in the following way: The volume of the cylinder will remain same. The initial volume of the cylinder is = A Х L Suppose, the area of cross-section becomes A/ and the resistance becomes R/. Hence, the resistance increases 4 times. Hope this helps you, Keep posting and have a nice day!

The initial velocity of a dropped ball is zero in the y (up-down) direction. After it is dropped gravity causes an acceleration, which causes the velocity to increase. F = ma, The acceleration due to gravity creates a force on the mass of the ball.

So? Whats the question? _______________________________ It doesn't matter what it is (well, if we ignore air resistance), in Earth's gravity the object will accelerate at 9.8 meters per second per second. Dropped from an altitude H, you can use the formula =(2/9.8*H)^0.5 to calculate the time it takes (in seconds) to the ground. In the absence of air resistance, it will take 0.808 seconds to fall. The speed of the falling object at any moment can be calculated as the time multiplied by 9.8 meters per second per second. In the absence of air resistance, the laundry bag will be falling at a speed of 7.9 meters per second when it hits.

8km/s

It is easiest to think of initial potential energy as the "distance" the object is able to fall. If it has not fallen the distance yet, then of course kinetic energy would be less.

Related questions

49

29.4

49

9.8m/s(5)= 49

,033

The acceleration of gravity is 9.8 m/s2Speed after 3 sec = (9.8 x 3) = 29.4 m/s

speed is decided by v = a(t), where t is your time variable and a is your acceleration constant. after 3 seconds, your velocity v = (9.8m/s2)(3s) = 29.4m/s

The acceleration of gravity is 32.1 ft/sec2 .After 3 seconds, the rock's downward speed is (3 x 32.1) = 96.3 ft/sec.(96.3 ft/sec) x (1 mi / 5,280 ft) = (96.3 / 5,280) (ft - mi / sec - ft) = 0.0182 mile/sec (rounded)

initial primary resistance is the first stage in revolt against the initial imposition of colonial rule. the africans ready resisted the ,imposition of colonial rule. they did not give the europeans the chance to impose their colonial policies.

how am i suppose to know

Fired ammunition from a firearm reaches a much higher initial velocity due to explosive propellant forces. In contrast, ammunition dropped from a high altitude reaches a terminal velocity where gravity pulling down is balanced by air resistance pushing up. The fired bullet maintains its higher velocity until slowed by air resistance and gravity, while dropped ammunition reaches a constant speed due to these opposing forces.

If you simply release an object, the initial velocity is always zero.