Volume

Chemistry

Top Answer

400 mL

(Explanation): again boyle's law PV=PV. Since the pressure is halved (500 to 250), then the volume must be doubled in order to maintain this equation. 200 x2=400 so that's the answer

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0BOYLES LAW The relationship between volume and pressure. Remember that the law assumes the temperature to be constant. or V1 = original volume V2 = new volume P1 = original pressure P2 = new pressure CHARLES LAW The relationship between temperature and volume. Remember that the law assumes that the pressure remains constant. V1 = original volume T1 = original absolute temperature V2 = new volume T2 = new absolute temperature P1 = Initial Pressure V1= Initial Volume T1= Initial Temperature P2= Final Pressure V2= Final Volume T2= Final Temperature IDEAL GAS LAW P1 = Initial Pressure V1= Initial Volume T1= Initial Temperature P2= Final Pressure V2= Final Volume T2= Final Temperature Answer BOYLES LAW The relationship between volume and pressure. Remember that the law assumes the temperature to be constant. or V1 = original volume V2 = new volume P1 = original pressure P2 = new pressure CHARLES LAW The relationship between temperature and volume. Remember that the law assumes that the pressure remains constant. V1 = original volume T1 = original absolute temperature V2 = new volume T2 = new absolute temperature P1 = Initial Pressure V1= Initial Volume T1= Initial Temperature P2= Final Pressure V2= Final Volume T2= Final Temperature IDEAL GAS LAW P1 = Initial Pressure V1= Initial Volume T1= Initial Temperature P2= Final Pressure V2= Final Volume T2= Final Temperature

You can calculate pressure and temperature for a constant volume process using the combined gas law.

In a small volume container the pressure is higher.

Pressure and volume are inversly proportional to each other, so as pressure increases by a factor of two, the volume is halved. See the 'gas laws'. P1 x V1 = P2 x V2 Where P1= initial pressure and V1 = initial volume P2 = final pressure and V2= final volume.

The gas pressure will be 1/3 of the initial pressure.

1/3 of the initial volume (Boyle-Mariotte law).

It would be half of the original volume. As you reduce the volume the pressure would increase and at half the original volume the pressure would be doubled.

The volume you would expect the gas to occupy if the pressure is increased to 40 kPa would be 50 liters.

The volume is now 1/2 of the initial volume.

initial volume = V1 final volume = V2 initial pressure = P1 final pressure = P2 = (1/2)P1 P1V1 = P2V2 P1V1 = (1/2)P1V2 P1 cancels; V1 = (1/2)V2 V2 = 2V2.

Boyle's law states that pressure is indirectly proportional to the volume. There fore as the pressure of a gas at 760 torr is changed to 380 torr, the volume will increase. Boyle's Law: P1 x V1 = P2 x V2 Rearranging leads to: P1 / P2 = V2 / V1 Substituting our values: 760 / 380 = V2 / V1 Thus the final volume will be twice the initial volume.

If pressure is held constant, volume and temperature are directly proportional. That is, as long as pressure is constant, if volume goes up so does temperature, if temperature goes down so does volume. This follows the model V1/T1=V2/T2, with V1 as initial volume, T1 as initial temperature, V2 as final volume, and T2 as final temperature.

The amplitude of the sound pressure is changed.

The initial pressure is halved. Use Boyle's law that relates pressure & volume at a constant temperature. P1V1 = P2V2 In this case the V1(initial volume) is doubled so V2 = 2V1 P2 = P1V1/V2 = P1V1/2V1 P2 = (1/2)*P1

Solids- stays the same Liquids- stays the same Gases- decreases You can use the formula PV/T=P2V2/T2 P=initial pressure V=initial volume T=initial temp P2=final pressure V2=final volume T2=final temp

With a decrease in pressure the volume of the balloon will increase

If you decrease the volume of the container, the pressure rises, and vice versa.

If temperature increases at a constant pressure the volume will increase. Temperature and volume both stick together T-V --->(DOWN)

For this you would use Boyle's Law, P1V1 = P2V2. The first pressure and volume variables are before the change, while the second set are after the change. In this case, the volume is being changed and the pressure has to be solved for. P1 = 1.30 ATM V1 = 31.4 L P2 = Unknown V2 = 15.0 L P1V1 = P2V2 1.30(31.4)=15.0P P= 2.72 ATM Looking at the question simply, you can get an estimate on the pressure because you can see that pressure and volume vary indirectly (if volume goes up, pressure goes down). If the volume is cut in half (roughly), then the pressure should increase by half.

The air can change by the temperature and volume held in the shape!

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