Find the average of your readings. Divide 220 volts into it and you will have your answer.
Current and voltage readings taken on the far right of a meter's scale provide greater inaccuracy that readings taken from mid scale on the meter.
The Voltmeter is used to measure the electrical potential difference between two points... so it's no use to connect it in Series , because the electrical potential difference between two points at the same line is zero ==> the readings will always be zero. The Ammeter is used to measure the electric current in a circuit... so it's no use to connect it in Parallel , because you want to know the current flowing in this wire. note the internal Resistance of the Ammeter is very little and very high for the Voltmeter --> so they will not affect the circuit.
You'd potentially damage the meter. Whether you do or not is immaterial; if the meter cannot measure the range of voltages you are expecting, it will not give accurate readings over that voltage range, thus you should not use it. Buy a different meter that will measure over that voltage range, or use a voltage divider circuit to get a lower voltage at a certain ratio of what is actually in the circuit (this may be difficult to do, or very simple depending on the circuit tested - the key is you do not want to load the circuit with the voltage divider network).
If all the readings are stored in an array, then the question becomes how to determine the maximum and minimum values in the array. This can be achieved with the following function: double min(double a[], const size_t size) { double min=a[0]; for( size_t i=1; i<size; ++i ) if(a[i]<min) min=a[i]; return(min); } double max(double a[], const size_t size) { double max=a[0]; for( size_t i=1; i<size; ++i ) if(a[i]<max) max=a[i]; return(max); } Note that when taking temperature readings, you will probably take several samples per day, possibly as often as once every second to obtain a high degree of accuracy. If so, your array will have 31.5 million elements each year.
to obtain more accurate readings
it is scalar as readings on Any scale is scalar.
No. A voltmeter measures potential difference (voltage). To measure power, a wattmeter is required. On the other hand, for a d.c. circuit only, you could use a voltmeter and an ammeter, and multiply their readings in order to calculate the power of a load.
vary the rheostat by step by step note out the two voltmeter readings
Voltmeter will give you opposite readings or will not work at all.
to reduce the the amount of anomalies and to improve the accuracy of the results.
Current and voltage readings taken on the far right of a meter's scale provide greater inaccuracy that readings taken from mid scale on the meter.
Add all the speed readings you have, e.g. from every second over a minute. Then you divide the answer by the number of readings you have.
Yes.
It could be when the positive wire is plugged in the negative slot and the negative wire is plugged in the positive slot. This can make the readings negative.
inability of authors to know every angle of every story.
A typical micrometer screw gauge has a maximum accuracy of ±0.005 mm (0.01 mm readings) whereas a vernier caliper has a typical maximum accuracy of ±0.05 mm (0.1 mm readings). Of course, different versions might have better or worse accuracy. They are also used differently because of their different shapes and forms.
Direction only. If you reverse the connections to your voltmeter or ammeter you get the same size readings but the directions are indicated to be the opposite way around, by reversal of sign.