Sulphur burns in Oxygen to form Sulphur dioxide in the following reaction: S+O2=SO2 Sulphur dioxide has a capability of reacting with oxygen to form Sulphur trioxide in the following reaction: 2SO2+O2=2SO3 By Prince Sambo Metallurgist
2S+3O2 => 2SO3
this is the complete combustion of sulphur. It uses 1.5 moles of oxygen per mole of sulphur
S+o2 -> so2
S + O2 = SO2 also 2 S + 3 O2 = 2SO3
2ch3sch3 + 9o2 ----> 4co2 + 6h2o 2so2
H2s + 3/2 o2 --> h2o + so2
The oxidation number of sulphur in H2S is 2.
the anwer is false
Bromine is not combustible
Ag2S3 + H2-------> Ag + H2S ( Write Out) Ag2S3 + 3H2-------> 2Ag + 3H2S ( Balanced) Reaction= single replacment
H2SO4 + CaS = CaSO4 + H2S
CuCl2 + H2S --> CuS + 2HCl Yes, this is the balanced equation here.
The oxidation number of sulphur in H2S is 2.
The balanced equation is as follows: 2Ag + H2S --> Ag2S + H2
the anwer is false
Bromine is not combustible
For complete combustion, the equation is C6H12 + 12 O2 = 6 CO2 + 6 H2O.
Ag2S3 + H2-------> Ag + H2S ( Write Out) Ag2S3 + 3H2-------> 2Ag + 3H2S ( Balanced) Reaction= single replacment
H2SO4 + CaS = CaSO4 + H2S
The complete combustion of ethanol in oxygen proceeds according to the balanced equation C2H6O + 3 O2 -> 2 CO2 + 3 H2O.
When the combustion is complete, the balanced equation is: C7H16 + 11 O2 -> 7 CO2 + 8 H2O.
C53+H778=undecane
helium is chemically inert and doesn't undergo combustion reaction