The molar mass of ammonia is about 17 grams, so that 3 moles would have a mass of 51 grams.
That amount of ammonia contains two moles of hydrogen gas. One mole of hydrogen gas weighs 2.016 grams. Therfore 3.75 grams of ammonia contains two moles of hydrogen.
2.8 moles of gold would be 550g of gold. Multiplying the amount of moles by the molar mass (197.0 grams/moles) will give you the grams by cancelling out the moles units.
1 mole equals 6.022 x 10 to the 23 molecules
Say you have 100 grams of the compound. If so, then you would have 3.1 grams H, 31.5 grams P, and 65.4 grams O. Convert these to moles: 3.1 grams H ÷ 1.01 grams/mol = 3.07 moles H 31.5 grams P ÷ 31.0 grams/mol = 1.02 moles P 65.4 grams O ÷ 16.0 grams/mol = 4.09 moles O Divide each of these by the smallest number, which is 1.02: 3.07 ÷ 1.02 = 3 1.02 ÷ 1.02 = 1 4.09 ÷ 1.02 = 4 These are your ratios. The empirical formula is then H3PO4
Assume the compound has a molar mass of 100 grams, from the information given, 32.2 grams is Calcium and 67.8 grams is Nitrogen.You then find the moles of each, which would be moles of Ca and moles of N.Dividing the two moles gives you the mole fraction: which we approximate to 6. This means that for every 1 mole of Ca, there are 6 moles of N, thus the answer is
The molar mass of ammonia is about 17 grams, so that 3 moles would have a mass of 51 grams.
The molar mass of ammonia is about 17 grams, so that 3 moles would have a mass of 51 grams.
3 moles of ammonia is 51grams. One mole is 17 grams.
That amount of ammonia contains two moles of hydrogen gas. One mole of hydrogen gas weighs 2.016 grams. Therfore 3.75 grams of ammonia contains two moles of hydrogen.
The mass would be approximately 92 grams.
The mass of 3 mol of ammonia is 51,093 g; the number of ammonia molecules in 3 moles is18,066422571.10e23.
92
224 grams of Oxygen will be in 2 moles of Potassium dichromate.
You can only calculate the empirical formula because you do not have a mass of this compound given. To do the empirical formula assume 100 grams and change percent to grams. Get moles. 80 grams Carbon (1 mole C/12.01 grams) = 6.66 moles C 20 grams hydrogen (1 mole H/1.008 grams) = 19.84 moles H the smallest becomes 1 in the empirical formula and the other number is divided by it, Thus; H/C 19.84 moles H/6.66 moles C = 2.9, which we call 3 so, CH3 --------------- is the empirical formula To get the molecular formula tour question needed to read; How to calculate molecular formula from such ans such mass of compound with these percentages of elements, Which, of course, your question did not provide. Then you would have divided that given mass by the mass total of the elements of the empirical formula, got a whole number by which you would have multiplied the numbers of your empirical formula to get molecular formula.
N2 + 3H2 -> 2NH3 3 moles hydrogen gas. You should know that because of the formula of ammonia.
NH3, or ammonia, has a molar mass of 17.031 g/mol. So .500 moles of the substance would equal 8.5155 grams.
The mass of 2 moles of ethyl alcohol would be 92,14 grams.