The equation for the fission of deuterium and tritium?

Answer 1

1 -_- it was One!

Answer 2

1 -_- it was One!

Answer 3

3 apex

it was 2 for me

Answer 4

(1) 21D + 31T → 42He ( 3.5 MeV ) + n0 ( 14.1 MeV )

(2i) 21D + 21D → 31T ( 1.01 MeV ) + p+ ( 3.02 MeV ) 50%

(2ii) → 32He ( 0.82 MeV ) + n0 ( 2.45 MeV ) 50%

(1) represents a reaction between deuterium and tritium, which are both isotopes of hydrogen. This is the most likely reaction to be harnessed for power production as it is the easiest to achieve with man-made equipment, though this is still in the experimental phase and continuous power production has never been achieved yet.

(2) represents a reaction between nuclei of deuterium alone, which can go two ways as shown. This would be preferable to (1) which requires production and handling of tritium, whereas all the deuterium needed can be obtained from ordinary water (deuterium combined with oxygen is heavy water) NB The Wikianswers format does not show the correct notation used to denote the nuclear isotopes so it may be difficult to understand the equations, but you can see the originals at Wikipedia 'Nuclear Fusion'

Answer 5

Deuterium and tritium cannot fission, so there is no equation.

Perhaps you meant fusion instead, if so it is:

D + T --> He + n + 17.59 MeV

Answer 6

• Chemical reaction: D2 + T2 = 2DT
• Nuclear reaction: D + T --> He + n + 17.59 MeV

Answer 7

Apex. The answer is 2.

Answer 8

3-3