The length and width of a rectangle are 8 inches and 4 inches respectively What would be the area of one of the triangles formed from drawing a diagonal in the rectangle?
diagonal cuts the rectangle into two congruent triangles.
32/2 = 16
To find interior angle measurements, you must divide the shape into triangles by drawing diagonal lines. The diagonal lines draw triangles, and the interior angle measure of triangles are always 180 degrees. The sum of interior angles of an octagon is 1080 degrees. How ever many triangles you have, multiply it by 180. See octagons in the link for more help,
Divide the rectangle in half, so you have two squares. Then cut each of these squares in half by drawing a straight line from the top left hand corner to the bottom right hand corner. Then you'll have four right angle triangles. * * * * * A rectangle, divided in half need not give a square. Try it with an A4 sheet of paper. A much simpler answer is to draw the two diagonals.
I would suggest that you draw the picture of a test tube in MS Word because it is much easier. You only need 3 drawing objects to create the test tube. These drawing objects are : Rounded Rectangle , Arc, and Rectangle. Use the Rectangle to cover the top part of the Rounded Rectangle and then click Shape Line > No Line. After that, draw two arcs to create the brim. Finally, Group these drawing…
How do you create three different drawings showing a number of circles and triangles in which the ratio of circles to triangles is 2 3?
Lever arm rule referrers to the similarity of triangles (similar triangles are the ones which have corresponding equal angles). They have the property of having the same ratio between the corresponding edges. This is in fact the lever-arm rule: the ratio between the lengths of the corresponding edges of two similar triangles are the same. By "corresponding" edges, one understands the edges of the triangles which oppose congruent angles. For exemplification, let's take a triangle…
A hexagon (six-sided polygon) can be divided into 4 triangles by drawing all of the diagonals from one vertex (only three lines can be drawn in this case, since each vertex already connects to two others on the edges of the form). If you instead drew lines from the center to each vertex, you would get 6 triangles.
How can you create two right triangles and an isosceles trapezoid by drawing two straight lines through a square?
The sides of the triangle will always meet at angles such that two of them will appear 'diagonal'. But these are not defined as diagonal lines. There are actually no diagonals intersecting any triangle. Try drawing one and connecting the vertices - it doesn't work and you simply end up tracing over the lines that define the triangle.
To find the diagonal, use the Pythagorean theorem by drawing a diagonal through the square. You then have two sides that should equal the hypotenuse ( or diagonal). The equation should look like 8^2 + 8^2 = h^2. or 64+64= h. 128=h take the square root of 128 and you have your answer. the answer should be around 11.