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The answer is 9. Let's first use and example, then view it conceptually. If we have scores of 3, 4, 5, 6, and 7, the mean will be five. (3 + 4 + 5 + 6 + 7)/5 = 25/5 or 5 If we add 4 to each of those scores we will then have: (7 + 8 + 9 + 10 + 11)/5 = 45/5 = 9 To see that this will work for all sets of scores, think of the formula for the mean: (a1 + a2 + a3 ... + an)/n = original mean Where a represents a single score in the distribution and n = number of scores in the sample. If we were to add 4 to each of the scores, then: [(a1+4) + (a2+4) + (a3+4) ... + (an+4)]/n [(a1 + a2 + a3 ... + an)+4n]/n [(a1 + a2 + a3 ... + an)/n] + 4 original mean + 4

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Q: The mean of a sample distribution is 5.0 If 4 were added to each score in the distribution the mean of the distribution would be?
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