Out of these possible answers A) Ba(NO3)2(aq) + K2SO4(aq) -> BaSO4(s) + 2KNO3(aq)
B) HCl(aq) + NaOH(aq) -> NaCl(aq) + H2O(l)
C) MgO(s) + H2)(l) -> Mg(OH)2(s) D) 2SO2(g) + O2(g) -> 2 SO3(g) E) 2H2O(l) -> 2H2(g) + O2(g)
It is called the oxidation process. Under this the element looses the electron so it's oxidation state increases.
The oxidation number of an element depend on another element it react with to form a compound e.g manganese(iv)oxide mno4 the oxidation number of oxygen there is four while the oxidation number of manganse is 7 in most radox reaction the oxidation number of oxygen is usually 4 when writing the full equation
2H2O2 <-> H2O + O2 the oxidation number of each O in H2O2 is -1 the oxidation number in H2O is -2 the oxidation number in O2 is zero. The average oxidation number of oxygen atoms on both sides of the equation. is the same. So overall the net change to oxygen is zero one is reduced two are oxidised. Looked at from the viewpoint of the oxygen atoms in O2 they started off with oxidation number of -1 and have ended up with 0, so they have been oxidised. (oxidation is loss of electrons, and therefore an increase in oxidation number.)
An oxide is the product of an oxidation reaction, a reaction with oxygen.
the answer is -2.Related Information:The oxidation number of oxygen when it appears as an element is 0. The oxidation number in all compounds but peroxides is -2. The oxidation number of oxygen in peroxides is -1.
Atomic oxygen has oxidation number 0. Molecular oxygen also has 0 as oxidation number. It would be the same for five oxygen molecules as well.
No. Oxidation is the loss of electrons by an atom, or equivalently an increase in the oxidation number of that atom. Rust formation is one example of oxidation.
oxygen, redox
No. The oxidation numbers of nitrogen and oxygen do not change.
The oxidation number of an element depend on another element it react with to form a compound e.g manganese(iv)oxide mno4 the oxidation number of oxygen there is four while the oxidation number of manganse is 7 in most radox reaction the oxidation number of oxygen is usually 4 when writing the full equation
2H2O2 <-> H2O + O2 the oxidation number of each O in H2O2 is -1 the oxidation number in H2O is -2 the oxidation number in O2 is zero. The average oxidation number of oxygen atoms on both sides of the equation. is the same. So overall the net change to oxygen is zero one is reduced two are oxidised. Looked at from the viewpoint of the oxygen atoms in O2 they started off with oxidation number of -1 and have ended up with 0, so they have been oxidised. (oxidation is loss of electrons, and therefore an increase in oxidation number.)
The oxidation number of oxygen is -2 in most of its compounds
Combustion is an oxidation reaction - a reaction with oxygen.
Oxidation means addition of oxygen. When oxygen is added to a compound, it is said to be oxidised.
An oxide is the product of an oxidation reaction, a reaction with oxygen.
A reaction witrh oxygen is called oxidation. Generally oxidation involve lose of electrons.
the answer is -2.Related Information:The oxidation number of oxygen when it appears as an element is 0. The oxidation number in all compounds but peroxides is -2. The oxidation number of oxygen in peroxides is -1.
In the compound Co2O3 cobalt has an oxidation number of 3 while oxygen has an oxidation number is -2.