No. Assuming the measure of the arc is in some units of length along the curve, you have to divide the result by the circumference of the circle.
Basically, you need to multiply the area of the whole circle by the fraction of the whole circle that the sector accounts for.
For A+ it's 20
true
The area of the circle is(17,640)/(the number of degrees in the central angle of the sector)
Area of whole circle = pi*r2 = 64*pi Area of Sector = Area of Whole Circle * Angle of Sector/Angle of Whole Circle = Area of Whole Circle * 120/360 = Area of Whole Circle / 3 = 64*pi/3 = 67.0 to the nearest tenth.
The area of the full circle is (pi) R2 = 64 pi.We call a full circle "360 degrees".The 300-degree sector is (300/360) = 5/6 of the full circle, so its area is(5/6) x (64 pi) = 167.55 square units (rounded)
fulse
Area of sector/Area of circle = Angle of sector/360o Area of sector = (Area of circle*Angle of sector)/360o
sector
That would certainly do it.
Divide the area of the sector by 360 and multiply it to the area. The area of the sector is 5 square inches.
Multiply ( pi R2 ) by [ (angle included in the sector) / 360 ].
Multiply ( pi R2 ) by [ (angle included in the sector) / 360 ].
Sector
Divide the angle sector by 360 and multiply it by 24 square meters. The area is equal to 3 square meters.
6.5
For A+ it's 20
It is found by: (sector area/entire circle area) times 360 in degrees