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Answered 2009-11-09 04:57:55

Since each event is independent, the probability remains at 0.5.

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The probability of tossing a coin 5 times and getting all tails is:P(TTTTT) = (1/2)5 = 0.03125 ≈ 3.13%


The probability of tossing a coin twice and getting tails both times is 1 in 4, or 25%. If you have already tossed a coin and had it land on tails, the probability that it will land on tails again the next time you toss it is 50%.






The probability of Tails on the first toss is 0.5 .The probability of Tails on the second toss is 0.5 .The probability of Tails on the third toss is 0.5 .The probability of Tails on the fourth toss is 0.5 .The probability of all four is (0.5 x 0.5 x 0.5 x 0.5) = 0.0625 = 6.25%


Since the probability of getting tails is 50% or 0.5, the probability of three tails would be 0.5*0.5*0.5=0.125 or 12.5 %


It may be that you don't have a "fair coin", or it might just be chance. To be sure - or rather, reasonably sure - you need to try tossing it quite a bit more times.


Because a coin is two-sided, 50/50 is always the probability. Unless your coin lands on the grass (on the lawn), then it will probably land on its edge.


If you look at the as the probability of getting 1 or more tail in 4 coin tosses, you would then calculate the probability of tossing 4 heads in a row and subracting that from 1. The probability fo tossing 4 heads is 1/2 * 1/2 * 1/2 * 1/2 = 1/16. 1 - 1/16 = 15/16.


The probability of getting 3 is virtually 1. It is 1.76 septillionths less than 1.


The probability is 0.5The probability is 0.5The probability is 0.5The probability is 0.5



The probability of getting zero tails is 1/2. The probability of getting zero tails twice in a row is 1/2 x 1/2 = 1/4. The probability of getting zero tails three times in a row is 1/2 x 1/2 x 1/2 = 1/8, etc... .


The probability to get tails once is 1/2 (for a fair coin) The probability to get tails twice = the probability to get it once x the probability to get it a second time The probability to get tails 4 times in a row is (1/2)4=1/16 The probability to get tails n times in a row is (1/2)n=1/2n The same thing is also true for heads (same probability: 1/2 each time)



The probability of tossing a coin 9 times and getting at least one tail is: P(9 times, at least 1 tail) = 1 - P(9 heads) = 1 - (0.50)9 = 0.9980... ≈ 99.8%


There are 2^5 (2*2*2*2*2), or 32, possible outcomes of tossing a coin 5 times. Only one of those outcomes does not contain any tails. This leaves us with 31/32, or 97% chance of at least one toss coming up tails.


5 independent events, each of them with a probability of 1/2; you need to multiply all together, so you get (1/2) to the power 5.Note: any other specific combination you can get when throwing a coin 5 times - for example, head, tails, head, tails, head - will have the same probability.


P(4T1H)) = 5C4 ∙ (0.5)5 = 5/32 = 0.15625 ≈ 15.6% where 5C4 = 5!/[3!∙(5-3)!] = 5


The probability of getting exactly seven tails if you flip a coin eight times is: P(7T1H) = 8∙(1/2)8 =0.03125 ≈ 3.1%


25% or 0.25 Probability of one tail is 0.50. Since two tails are independent events, the probability is 0.5 x 0.5 = 0.25


The probability of each coin flip, independently, is 0.5 or 50%. The probability of getting one result (either heads or tails) four times in a row is 0.5 to the fourth power or 0.0625, which equals 6.25%


That depends how many times you flip the coin.



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