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Q: Two rectangles have a perimeter of sixteen inchesName two possible areas for each rectangle?
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What is the relationship for perimeter and area for rectangle?

There is no relationship between the perimeter and area of a rectangle. Knowing the perimeter, it's not possible to find the area. If you pick a number for the perimeter, there are an infinite number of rectangles with different areas that all have that perimeter. Knowing the area, it's not possible to find the perimeter. If you pick a number for the area, there are an infinite number of rectangles with different perimeters that all have that area.


Two rectangles have an area of 81 square inches name two possible perimeter for each rectangle?

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How do i draw all possible rectangles with a perimeter of 30cm and sides whose lengths are whole numbers?

The answer is, you can draw a rectangle with these measurements: 6cm and 9cm 5cm and 10cm 7cm and 8cm


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There are infinitely many possible rectangles. Let A be ANY number in the range (0,6] and let B = 12-A. Then a rectangle with width A and length B will have a perimeter of 2*(A+B) = 2*12 = 24 units. Since A is ANY number in the interval (0,6], there are infinitely many possible values for A and so infinitely many answers to the question.


Two rectangles have a perimeter of 16 inches Name two possible areas for each rectangle?

* It is unclear if the question is asking about two rectangles, each with a perimeter of 16, or two rectangles whose perimeters sum to 16. This answer assumes the former.Other than the 4x4 square, which coincidentally has both a perimeter and area of 16, some examples would be:1 x 7 rectangle : perimeter 16 in. , area 7 sq. in2 x 6 rectangle : perimeter 16 in., area 12 sq. in3 x 5 rectangle: perimeter 16 in., area 15 sq. inYou can calculate that for a given perimeter, the largest area is found in the square with a side measurement of P/4, i.e. the length and the width are the same.


What is the base and the height of a rectangle if the perimeter 24?

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Rectangular with a perimeter of 9 cm?

There are infinitely many possible rectangles. Suppose A >= 2.25 cm is the length of the rectangle. and B = 4.5 - A cm is the width. Then perimeter = 2*(A + B) = 2*(A + 4.5 - A) = 2*4.5 = 9 cm Also, it is easy to show that A >=B so that A and B cannot swap places. For each of the infinitely many values of A, you have a rectangle with perimeter 9 cm.


Possible rectangles with a perimeter of 18 cm and whole-number lengths of sides?

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What is the larest area possible for any rectangle with the same perimeter?

(p/4)2, where p is the perimeter.


Is it possible to have a rectangle with the same perimeter and area?

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What is the least possible perimeter for a rectangle with an area of 169ft2?

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