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# Under what conditions is average velocity equal to instantaneous velocity?

When there is no acceleration or when there is constant acceleration. When either of these cases is present, the graph of velocity versus time will be linear. When there is linear velocity, the average velocity will equal the instantaneous velocity at any point on the graph.

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## Related Questions

Generally it is a Yes. Instantaneous velocity is the exact velocity at a particular time in the course of the movement. However, average velocity is the average of all the instantaneous velocity over a period of time. It is also known as speed in everyday life. As a result, the movement of an object over a time period under varying velocity denotes a varying instantaneous velocity which could be different from the average velocity. It is however, possible that the instantaneous velocity equates to the average velocity at a certain point over the duration of movement. For example, a ball is traveling at instantaneous velocity of 99m/s at t=1s , 100m/s at t=2s and 101m/s at t=3s. the average velocity over the 3s period is hence 100m/s which coincides with the instantaneous speed at t=2s.

The magnitude of average velocity of an object equal to its average speed if that object is moving with CONSTANT velocity.

if under uniform acceleration or deceleration v = u + (a*t) where: v = instantaneous velocity u = initial velocity a = acceleration (negative if decelerating) t = time elapsed

That would be the case if the object moved only among a straight line, and only in one direction (i.e., it didn't move back and forth).

it is defined as the average velocity with which the free eloctrons get drifted towards the positive ends of the conductor under the influence of an external electric field applied

The area between the graph and the x-axis is the distance moved. If the velocity is constant the v vs t graph is a straight horizontal line. The shape of the area under the graph is a rectangle. For constant velocity, distance = V * time. Time is the x-axis and velocity is the y-axis. If the object is accelerating, the velocity is increasing at a constant rate. The graph is a line whose slope equals the acceleration. The shape of the graph is a triangle. The area under the graph is &frac12; * base * height. The base is time, and the height is the velocity. If the initial velocity is 0, the average velocity is final velocity &divide; 2. Distance = average velocity * time. Distance = (final velocity &divide; 2) * time, time is on the x-axis, and velocity is on the y-axis. (final velocity &divide; 2) * time = &frac12; time * final velocity ...&frac12; base * height = &frac12; time * final velocity Area under graph = distance moved Most velocity graphs are horizontal lines or sloping lines.

While a body in motion cannot have zero average velocity, there are many examples where the average velocity - after selected intervals - is zero. For example: a pendulum, or any object under simple harmonic motion, after a complete number of cycles; a rotating object (point on a wheel or hand of a clock) after a whole number of circuits.

The average lifespan of a galah, under ideal conditions, is 60 years.

An object can indeed change velocity when its acceleration is constant as long as its acceleration is not zero. (If an object is not accelerated, its velocity cannot change.) Recall that velocity is speed plus a direction vector. A rock is falling under the force of gravity from a mile up. Its acceleration is constant. The force of gravity is not increasing or decreasing is it? No, it is not. (That's why we call it a gravitational constant.) So the rock is operating under constant acceleration (of one earth gravity, or 1 g) and its velocity is increasing. At some point in its fall, at some exact moment in time, our rock had an instantaneous velocity of 20 meters per second down. (Down is the direction vector.)

&quot;Under field conditions&quot; is more idiomatic.

If you double velocity the speed increases by [itex] sqrt(2) [/itex] You go twice as fast? The momentum is doubled? The KE is multiplied by four? OK, none of that works under some specific conditions. For example, if the initial velocity is zero, none of the above happens.

Momentum like mass will always be conserved in any process. Momentum is the product of mass and velocity of the object. It is symbolically denoted as p=m*v where p = momentum, m = mass and v = velocity

Under some conditions, they can approach thirty years or more.

The velocity of an object (v) at any particular instant is the distance covered by that object (s) divided by the time interval (t) taken to cover the distance. When the velocity is changing, the instantaneous velocity is the distance covered in a very, very short time divided by the very, very short period taken to cover it. In differential calculus, this would be denoted by v = ds/dt By definition, then, s is the integral of v with respect to time. Graphically, this is the area under the velocity-time graph.

There are many different locations in the world. The locations all have incredibly different average climates and temperatures under different conditions.

With an average orbital speed of 5.43 km a second, this equates to just under 20,000 km per hour.

you can't....it's merely impossible! Assuming it is a graph of velocity vs time, it's not impossible, it's simple. Average velocity is total distance divided by total time. The total time is the difference between finish and start times, and the distance is the area under the graph between the graph and the time axis.

Derivitives of a velocity : time graph are acceleration and distance travelled. Acceleration = velocity change / time ( slope of the graph ) a = (v - u) / t Distance travelled = average velocity between two time values * time (area under the graph) s = ((v - u) / 2) * t

Scientists predict that their average lifespan under field conditions is 4-8 years.

To fully cure I give it 24 hours under average conditions.

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