answersLogoWhite

0


Best Answer

It DOES NOT stop for a 'few seconds' . It stop only for an instant as its movement changes from upwards to downwards.

User Avatar

lenpollock

Lvl 15
2y ago
This answer is:
User Avatar
User Avatar

Christodea Otsen

Lvl 1
2y ago
Can I have your number ...this is mine +233576345172. I'm from Ghana

Add your answer:

Earn +20 pts
Q: What makes a thrown upwards body to stop for some few seconds before desendeing down?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

Which force acts on a body thrown vertically upwards?

Gravity


When a rock thrown straight upwards gets to the exact top of its path is?

zero


When a body is thrown upwardhow many forces act on it?

when abody is thrown upward,how many forces act on it?what is the role of the force with which the body has been thrown upward? After a body is thrown upwards, you have gravity pulling it down and friction slowing it.


What are the important laws of physics?

One I know is that all is thrown upwards come back downwards.


Has Daniel Radcliffe thrown up before?

Yes he has thrown up before


A baseball thrown 38 meters in 1.7 seconds?

22.35294117647059


A balls is thrown upwards with a velocity of 10 ms How high does it go?

The ball goes up 5.1 meters.


Why does a ball fall when thrown?

Because it is heaver than the air. Earth attracts all bodies towards its center. So when a body is thrown upwards it rises to height and fall downwards.


If after an object is thrown no other fone and ads on it except gravity What are the vertical and horizontal components of its acceleration vector?

If the object is thrown upwards, the vertical acceleration is negative and the horizontal acceleration is zero.


How fast must an object be thrown up if it is to stay in the air for 5 seconds before hitting the ground again?

An object can be thrown vertically upwards or at an angle to the ground, in both cases it is needed that time of flight be 5 seconds. This means it's time of ascent (going up) is 2.5 seconds and time of descent(coming down) is also 2.5 seconds. So, it reaches highest point 2.5 seconds after it is thrown. At highest point the vertical component of velocity1 of the object becomes zero for an instance.Now, kinematics equation can be used to solve this.v = uy - g*twhere v is final velocity at top =0. uy is initial vertical velocity1. g is accleration due to gravity(9.8ms-2). t is time of ascent.putting values we get.0 = uy - 9.8 * 2.5or uy = 24.5 ms-1So we need to throw an object with vertical velocity = 24.5 meters per second so that it remains in air for 5 seconds.1. If object is thrown at an angle then vertical component of velocity of projection is taken.If object is thrown vertically upwards then vertical component of velocity of projection issame as velocity.vertical component of velocity of projection(uy) = u*sin(θ), where u is velocity of projectionand θ is angle of projection with respect to horizontal.2. Accleration due to gravity is different for different places. 9.8ms-2 is an approximatevalue.3. Here, air resistance and wind speeds have been neglected as they make the calculation verytedious and they are always varying from time to time and place to place.


How long does it take for a baseball thrown at 99 mph to go 60 feet 6 inches?

0.42 seconds.


How do you beat level 9 on fragger atlantis?

Your first grenade must be thrown into the notch near the thrower, which blows out the trap door upwards